The <em>complement </em>C'<em> </em>of some set C is essentially the set we get when we remove all of the elements of C from the universal set U.
Here, our universal set contains all of the numbers 1-16, and the set C contains all of the odd numbers between 1 and 16. If we were to put both of these sets in roster form:
If we remove all of the elements of C from the universal set U, we're left with the complement of C, which contains all of the <em>even numbers </em>between 1 and 16:
Answer:5
Step-by-step explanation:
Answer:
The correct answer to the following question will be "
".
Step-by-step explanation:
Give that the volume of the box = xyz cubic feet
Amount of jars which you can make = 
Let the volume of the removed clay = V cubic feet
As we know,
As we place the values in the equation above, we obtain
⇒ 
When multiplication is applied we receive
⇒ 
⇒ 
⇒ 
cubic feet
I think it’s 12 of the hexagon
Answer:
Désolé, mon français est terrible, je vais donc utiliser traduction automatique ici.
x est approximativement égal à 0.906 et -1.656
Step-by-step explanation:
x + (2x + 3) + 4x² - 9 = 0
4x² + x + 2x + 3 - 9 = 0
4x² + 3x - 6 = 0
Nous ne pouvons pas prendre en compte cela, nous allons donc passer par la résolution de x à la place.
Commençons par compléter le carré:
4x² + 3x = 6
4x² + 3x + 9 / 16 = 6 + 9 / 16
(2x + 3/4)² = 96 / 16 + 9 / 16
(2x + 3/4)² = 105 / 16
2x + 3/4 = ± √105 / 4
2x = -3/4 ± √105 / 4
2x = (-3 ± √105) / 4
x = (-3 ± √105) / 8
x ≈ 0.906, -1.656
