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xxTIMURxx [149]
2 years ago
6

X² + 4x + 3 = 0Can someone please help me solve this quadratic equation ​

Mathematics
1 answer:
gavmur [86]2 years ago
8 0

Answer:

Step-by-step explanation:

x= -1 and -3

What when multiplied is +3 but when added is 4? 3 and 1. You then get (x+3)(x+1) is the first part of the answer. If you want to find x, set x+3 to 0. x+3=0. Then subtract 3 from both sides to get x by itself. x= -3. Do the same with the x+1.

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Perpendicular lines are like a plus symbol,
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Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.3 and P(B) = 0.7. If
Thepotemich [5.8K]

Answer:

See below

Step-by-step explanation:

What is P(A B)?

If A and B are mutually exclusive, then  

P(AB) = P(A∩B) = P(∅) = 0

What is P(A | B)?

By definition  

<em>P(A | B) =  P(A∩B)/P(B). </em>

Since  

P(A∩B) = 0, then P(A | B) = 0

Is P(A | B) equal to P(A)?

No, because P(A | B) = 0 and P(A) = 0.3

Are events A and B dependent or independent?

A and B would be independent if

P(A | B) = P(A) and P(B | A) = P(B)

But both P(A |B) and P(B | A) equals 0 and P(A) = 0.3, P(B) = 0.7

Hence, <em>A and B are dependent. </em>

A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and that if events are mutually exclusive they must be independent. Is this statement accurate?

No, it is not.

As we already saw, A and B are mutually exclusive but they are not independent.

What general conclusion would you make about mutually exclusive and independent events given the results of this problem?

If A and B are not empty events which are mutually exclusive, they can never be independent.

6 0
3 years ago
Andrea can rollerblade faster than most skateboarders, she can go 250 feet in 10 seconds. At this rate, how many miles can she r
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3 0
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Y = square root of x + 6
wariber [46]

Answer:

Step-by-step explanation:

x^{2} + 36

5 0
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Please tell me the answer plsss i will be sure to mrk u brainliest for the best answer
Finger [1]

Step-by-step explanation:

2^3 X 3^-4 X 5^2 / (2x5)^2 X 2 X 3^2 X 3^-6

I will simply the expression on the RHS if the bracket first

2^2 X 5^2 X 2 X 3^2 X 3^-6

= 2^3 X 3^-4 X 5^2

So, putting them together

Both sides have th same expression

They cancel out each other

Answer : 1

5 0
2 years ago
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