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anygoal [31]
4 years ago
6

How do you subtract a positive fraction from a negative fraction?

Mathematics
1 answer:
Usimov [2.4K]4 years ago
8 0
You need the same denominator
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Try to find x & y. I need it so much please
kumpel [21]

Answer:

x = 3

y = 5

Step-by-step explanation:

Using theorem of similar triangles, we have,

(6 + x)/6 = (7 + 3.5)/7

(6 + x)/6 = 10.5/7

Cross multiply

7(6 + x) = 10.5(6)

42 + 7x = 63

7x = 63 - 42

7x = 21

x = 21/7

x = 3

Thus:

7.5/y = (7 + 3.5)/7

7.5/y = 10.5/7

Cross multiply

7.5*7 = 10.5*y

52.5 = 10.5*y

Divide both sides by 10.5

52.5/10.5 = y

y = 5

3 0
3 years ago
Write a recursive rule: <br><br>-2,0,2,4,6​
bearhunter [10]
Write a recursive rule for the sequence.

-2,0,2,4,6

STEP 1:

a1 = -2

a2 = 0

a3 = 2

STEP 2:

d = a2-(a1)=a3

= d = 0-(-2)=2

STEP 3:

An = a+(n-1)d

ANS:

6 0
3 years ago
A circle has a diameter of 12 units, and its center lies on the x-axis. what could be the equation of the circle? check all that
wariber [46]

The equation of a circle with radius of 6 units and center on the x axis could be (x - 6)² + y² = 36

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

The circle has a diameter of 12 units. Hence, radius = 12/2 = 6 units.

The center of the circle is at x axis (*, 0), the equation could be:

(x - 6)² + (y - 0)² = 6²

(x - 6)² + y² = 36

The equation of a circle with radius of 6 units and center on the x axis could be (x - 6)² + y² = 36

Find out more on equation at: brainly.com/question/2972832

#SPJ4

5 0
2 years ago
A rucksack can hold a maximum of 6 kg.
ratelena [41]

Answer:

9 textbooks!

Step-by-step explanation:

Rucksack can hold = 6kg

Mass of textbook = 680g

So, here we need to show the division for finding the number of textbooks it can hold.

680 g in KG's = 0.68

Now, 6/0.68

That is 8.82 ( Round off = 9 textbooks)

5 0
3 years ago
Read 2 more answers
What are the solution of x^2-2x+17=0
ddd [48]

Answer:

<h2>x = 1 - 4i or x = 1 + 4i</h2>

Step-by-step explanation:

x^2-2x+17=0\qquad\text{subtract 17 from both sides}\\\\x^2-2x=-17\\\\x^2-2(x)(1)=-17\qquad\text{add}\ 1^2\ \text{to both sides}\\\\x^2-2(x)(1)+1^2=-17+1^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-1)^2=-17+1\\\\(x-1)^2=-16

x-1=-4i\ \vee\ x-1=4i\qquad\text{add 1 to both sides}\\\\x=1-4i\ \vee\ x=1+4i

4 0
3 years ago
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