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Leno4ka [110]
3 years ago
12

I need help on this math assignment I can't find the right answer

Mathematics
2 answers:
geniusboy [140]3 years ago
6 0

Answer:

whats the question and all of these triangles have a right angle so they are right triangles

Tasya [4]3 years ago
4 0

Answer: 1. sqrt(19); 2. sqrt (96); 3. sqrt (105); 4. sqrt (28)

Step-by-step explanation: All you have to do is use Pythagoras' Theorem.

So, e.g. in question 1, the equation would be x^2 + 9^2 = 10^2.

x^2 = 100 - 81

x^2 = 19

Therefore, x = sqrt (19) or (19)^1/2

BTW, sqrt means square root.

And now you apply it for everything else.

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What is f(a+2)<br> A.<br> B.<br> Or<br> C.
Damm [24]

Answer:

B

Step-by-step explanation:

f(x) = 3(x + 5) + 4/x

To find f(a + 2) , put a + 2 in place of every x

f(a + 2) = 3 (a + 2 + 5) + 4/(a + 2)

f(a + 2) = 3 (a + 7) + 4/(a + 2)

8 0
3 years ago
Read 2 more answers
*BRAINLIEST* please help!!! the option for the second blank are the same as the first one
AlekseyPX

Answer:

Diverges

Step-by-step explanation:

Hope i helped:)

6 0
3 years ago
Read 2 more answers
.If 3x+ 6 = 5x -10,then the value of x is​
trapecia [35]

Answer:

X=8

Step-by-step explanation:

3x+ 6 = 5x -10

6+10=5X-3X

16=2X

X=8

4 0
3 years ago
The region r is enclosed by the curves y=4-4x2 and y=0
Misha Larkins [42]

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0

The intersection points will be

       y₁ = y₂

4 - 4x² = 0

        x = ±1

Then the area bounded by the curves will be

\rm Area = \int _{-1}^1 (y_1-  y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x  - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

6 0
2 years ago
When an amount of heat Q (in kcal) is added to a unit mass (kg) of a
lisov135 [29]

Answer:

The change in temperature per minute for the sample, dT/dt is 71.\overline {6} °C/min

Step-by-step explanation:

The given parameters of the question are;

The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)

The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min

Given that both dQ/dT and dQ/dt are known, we have;

\dfrac{dQ}{dT} = 0.18 \, (kcal/ ^{\circ} C)

\dfrac{dQ}{dt} = 12.9 \, (kcal/ min)

Therefore, we get;

\dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = {\dfrac{dQ}{dt} } \times \dfrac{dT}{dQ} = \dfrac{dT}{dt}

\dfrac{dT}{dt} = \dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = \dfrac{12.9 \, kcal / min }{0.18 \, kcal/ ^{\circ} C }   = 71.\overline 6 \, ^{\circ } C/min

For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

\dfrac{dT}{dt}  = 71.\overline 6 \, ^{\circ } C/min

8 0
3 years ago
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