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2 years ago

I need help on this math assignment I can't find the right answer

Mathematics

2 answers:

geniusboy [140]2 years ago

6 0

Answer:

whats the question and all of these triangles have a right angle so they are right triangles

Tasya [4]2 years ago

4 0

Answer: 1. sqrt(19); 2. sqrt (96); 3. sqrt (105); 4. sqrt (28)

Step-by-step explanation: All you have to do is use Pythagoras' Theorem.

So, e.g. in question 1, the equation would be x^2 + 9^2 = 10^2.

x^2 = 100 - 81

x^2 = 19

Therefore, x = sqrt (19) or (19)^1/2

BTW, sqrt means square root.

And now you apply it for everything else.

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2 years ago

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Evaluate f(-3) for f(x) = 2x.

Natasha_Volkova [10]

Answer: f(-3) = 2 x -3 = -6

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3 years ago

Can somebody help me with this?

lesya [120]

Answer:

141 °

since they are supplementary angles and they always add to 180 °

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2 years ago

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Use polynomial long division to rewrite the following fraction in the form q(x)+r(x)d(x), where d(x) is the denominator of the o

SOVA2 [1]

Step-by-step explanation:

p(x) = 2x^2+8x-12

d(x) = x + 1

r(x) = -13

q(x) = 2x + 6

$\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2x +6 \\ x + 1 \sqrt{ {2x}^{2} + 8x - 12} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: {2x}^{2} + 2x \\ \: \: \: \: \: \: \: \: \: \: \: \frac{ \: - \: \: \: \: \: \: - \: \: \: \: \: }{} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 6x - 12 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 6x + 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{ - \: \: - \: \: \: \: \: }{} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 13$

q(x)+r(x)d(x)

= 2x + 6 + (-13) * x + 1

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= (- 11x + 7)

6 0

3 years ago

Newton's Law of Cooling states that the rate of change of the temperature of an object, T, is proportional to the difference of

spin [16.1K]

Answer:

- 278.4°F

Step-by-step explanation:

Temperature of Object ( T ) = 1200° F

Temperature of surrounding ( M ) = 80°F

Time ( t ) = 1 hour

dT / dt ∝ ( M - T )

dT /dt ∝ | ( 80 - 1200 ) |

dT / dt = k ( 1120 )

(1200 - 830 ) / 1 = k ( 1120 )

hence k = ( 1200 - 830 ) / 1120

= 370 / 1120 = 0.33

what is the object's temperature (x )after 4 hours

( 1200 - x ) / 4 = 0.33 ( 1120 )

( 1200 - x ) / 4 = 369.6

hence x = 1200 - ( 4 * 369.6 )

= - 278.4 ° F

3 0

2 years ago