Please, I need help with this!! :(
1 answer:
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See diagram
I wrote that the degrees are 70 each because it is isocolese and 140/2=70
a.
to solve for the diagonal, I'm going to use trig to find the height and the base then use pythagorean theorem to find the diagonal
so
see I've drawn an auxiliry line to make a right triangle on the leftmost side
so
we want to find the height and base
sin(70°)=h/7
so 7sin(70°)=h≈6.57785
cos(70°)=base/7
so 7cos(70°)=base≈2.39414
now
the entire long base is 22, so that big triangle with the diagonal as the hyptonuse is 22-2.39414=19.6059
use pythagorean theorem, like 6.57785²+19.6059²=diagonal²
we get that the diagonal is about 20.68ft
b.
we got that the base was 7cos(70°)
2 of those bases so 22-14cos(70°)=17.2117ft or rounded 17.21ft
a. 20.68ft
b. 17.21ft
I wrote that the degrees are 70 each because it is isocolese and 140/2=70
a.
to solve for the diagonal, I'm going to use trig to find the height and the base then use pythagorean theorem to find the diagonal
so
see I've drawn an auxiliry line to make a right triangle on the leftmost side
so
we want to find the height and base
sin(70°)=h/7
so 7sin(70°)=h≈6.57785
cos(70°)=base/7
so 7cos(70°)=base≈2.39414
now
the entire long base is 22, so that big triangle with the diagonal as the hyptonuse is 22-2.39414=19.6059
use pythagorean theorem, like 6.57785²+19.6059²=diagonal²
we get that the diagonal is about 20.68ft
b.
we got that the base was 7cos(70°)
2 of those bases so 22-14cos(70°)=17.2117ft or rounded 17.21ft
a. 20.68ft
b. 17.21ft
Answer: 20 feet by 20 feet.
Step-by-step explanation:
1. You know that is the original measure of one side. Since it is a square, all its sides are equal.
2. Therefore, to solve the problem you only need to solve for , as you can see below:
- You have that:
- Then, you obtain the following quadratic equation:
- Apply the Quadratic formula to solve it:
- Then, you obtain:
3. The dimensions cannot be negative, therefore, the answer is: 20 feet by 20 feet.