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2 years ago

Does anyone know the answers???

Mathematics

2 answers:

Morgarella [4.7K]2 years ago

4 0

Answer:

16:3

17:4

18:1

19:1

Step-by-step explanation:

Katarina [22]2 years ago

4 0

Answer:

Answer for number 17.

Step-by-step explanation:

Simplifying

6(x + 4) = 3(4x + -2)

Reorder the terms:

6(4 + x) = 3(4x + -2)

(4 * 6 + x * 6) = 3(4x + -2)

(24 + 6x) = 3(4x + -2)

Reorder the terms:

24 + 6x = 3(-2 + 4x)

24 + 6x = (-2 * 3 + 4x * 3)

24 + 6x = (-6 + 12x)

Solving

24 + 6x = -6 + 12x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12x' to each side of the equation.

24 + 6x + -12x = -6 + 12x + -12x

Combine like terms: 6x + -12x = -6x

24 + -6x = -6 + 12x + -12x

Combine like terms: 12x + -12x = 0

24 + -6x = -6 + 0

24 + -6x = -6

Add '-24' to each side of the equation.

24 + -24 + -6x = -6 + -24

Combine like terms: 24 + -24 = 0

0 + -6x = -6 + -24

-6x = -6 + -24

Combine like terms: -6 + -24 = -30

-6x = -30

Divide each side by '-6'.

x = 5

Simplifying

x = 5

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What is the slope of the line through A(2, 6) and B(8, -1)

zimovet [89]

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2 years ago

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2 years ago

What is the sun of this question somebody tell me

Liono4ka [1.6K]

Answer:

2/10 +28/100
20+28/100
48/100
12/25

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1 year ago

Read 2 more answers

Can someone please explain how to do this!!!

DedPeter [7]

Hi there!

So we are given that:-

tan theta = 7/24 and is on the third Quadrant.

In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive.

Since we want to find the value of cos theta. cos must be less than 0 or in negative.

To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.

Using the Identity

$\large \displaystyle{ {tan}^{2} \theta + 1 = {sec}^{2} \theta}$

Substitute tan theta = 7/24 in.

$\large \displaystyle{ {( \frac{7}{24}) }^{2} + 1 = {sec}^{2} \theta }$

Evaluate.

$\large \displaystyle{ \frac{49}{576} + 1 = {sec}^{2} \theta} \\ \large \displaystyle{ \frac{625}{576} = {sec}^{2} \theta}$

Reminder -:

$\large \displaystyle{ sec \theta = \frac{1}{cos \theta} }$

Hence,

$\large \displaystyle{ \frac{576}{625} = {cos}^{2} \theta} \\ \large \displaystyle{ \sqrt{ \frac{576}{625} } = cos \theta} \\ \large \displaystyle{ \frac{24}{25} = cos \theta}$

Because in QIII, cos<0. Hence,

$\large \displaystyle \boxed{ \blue{cos \theta = - \frac{24}{25} }}$

Using the Pythagorean Theorem

$\large \displaystyle{ {a}^{2} + {b}^{2} = {c}^{2} }$

Define c as our hypotenuse while a or b can be adjacent or opposite.

Because tan theta = opposite/adjacent. Therefore:-

$\large \displaystyle{ {7}^{2} + {24}^{2} = {c}^{2} } \\ \large \displaystyle{49 + 576 = {c}^{2} } \\ \large \displaystyle{625 = {c}^{2} } \\ \large \displaystyle{25 = c}$

Thus, the hypotenuse side is 25. Using the cosine ratio:-

$\large \displaystyle{cos \theta = \frac{adjacent}{hypotenuse}}$

Therefore:-

$\large \displaystyle{cos \theta = \frac{24}{25} }$

Because cos<0 in Q3.

$\large \displaystyle \boxed{ \red{cos \theta = - \frac{24}{25} }}$

Hence, the value of cos theta is -24/25.

Let me know if you have any questions!

8 0

2 years ago