1) function 1/x, vertical stretch is 2/x 2) reflection over x axis is -2/x, 3) left shift is -2/(x+3) 4) down 4 units -2/(x+3) -4 it should be <span>B. y= -2/(x+3) -4</span>
hmmm first off let's convert the √3 +i to trigonometric form, and then use De Moivre's root theorem, bearing in mind that √3 and i or 1i are both positive, meaning we're on the I Quadrant.