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labwork [276]
2 years ago
14

How do you Simplify 6/3

Mathematics
2 answers:
Anna35 [415]2 years ago
8 0
You look for the greatest common factor and your answer is 2
ValentinkaMS [17]2 years ago
7 0
6/3=2 do not know how this is hard
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Math answer with work cause it need proof ASAP
Viktor [21]

Answer:

[See Below]

Step-by-step explanation:

__________________________

✦ Solve for (1*10)+(4*1)+(7*0.01)+(2*0.001):

__________________________

✦ Solve Parenthesis first:

  • (1*10)=\bold1\bold0
  • (4*1)=\bold4
  • (7*0.01)=\bold0\bold.\bold0\bold7
  • (2*0.001)=\bold0\bold.\bold0\bold0\bold2

__________________________

✦ Add all the values together:

  • 10+4+0.07+0.002=\bold1\bold4\bold.\bold0\bold7\bold2

__________________________

So Mikayla wrote the decimal correctly.

__________________________

~<em>Hope this helps Mate. If you need anything feel free to message me.</em>

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5 0
3 years ago
Which of the following describes the graph below
Law Incorporation [45]

Answer:

b

Step-by-step explanation:

7 0
2 years ago
Please help! Will give brainly, 50 points!! I'm stuck with this question and I don't get it!
pishuonlain [190]

Answer: The answer is x^2 + 4x - 3

Step-by-step explanation:

You just combine like terms, the only ones that can combine is the 6x and -4x. You just subtract them to get the answer of x^2 + 4x - 3.

7 0
3 years ago
Read 2 more answers
Quadrilateral ABCD is rotated 90° about the origin. What are the coordinates
Ilya [14]

Answer:

The Answer Would Be C. A'(-5, -5), B'(-5, -1). C'(-2,-1).

D(5, -1)

Quick math. ;)

6 0
3 years ago
Find the value of cos 28°​cos 62°​– sin 28°​sin 62°​
Romashka [77]
<h2>Answer:</h2>

cos 28°​cos 62°​– sin 28°​sin 62°​ = 0

<h2>Step-by-step explanation:</h2>

From one of the trigonometric identities stated as follows;

<em>cos(A+B) = cosAcosB - sinAsinB             -----------------(i)</em>

We can apply such identity to solve the given expression.

<em>Given:</em>

cos 28°​cos 62°​– sin 28°​sin 62°​

<em>Comparing the given expression with the right hand side of equation (i), we see that;</em>

A = 28°

B = 62°

<em>∴ Substitute these values into equation (i) to have;</em>

<em>⇒ cos(28°+62°) = cos28°cos62° - sin28°sin62°</em>

<em />

<em>Solve the left hand side.</em>

<em>⇒ cos(90°) = cos28°cos62° - sin28°sin62°</em>

⇒ 0 = <em>cos28°cos62° - sin28°sin62°     (since cos 90° = 0)</em>

<em />

<em>Therefore, </em>

<em>cos28°cos62° - sin28°sin62° = 0</em>

<em />

<em />

8 0
2 years ago
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