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DENIUS [597]
3 years ago
9

What is one half times 10

Mathematics
2 answers:
lys-0071 [83]3 years ago
7 0
That would be 5, all you need to do is divide by 2 or mltiply by 0.5 to get half of a number
ivolga24 [154]3 years ago
5 0
The answer is 5. if you have 10 and take away half, you have 5.
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What is the value of this expression when x= -6 and y= -1/2? 4(x2+3)-2y
Ostrovityanka [42]

Answer:y=-10

Step-by-step explanation:

y=-1/2 4(6(2)+3)-2y

+2y       6(2)            +2y

3y=-1/2 4(12+3)

multiplie 4 times 12 and 4 times 3

3y=-1/2 48+12

add 48 and 12

3y=-1/2 60

divide -1/2 and 60

3y/3=-30/3

y=-10

3 0
3 years ago
2 : 9, 12 : , and : 45.
Ber [7]

Answer:

Sorry. What's the question?

8 0
3 years ago
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Which of these statements is true for f(x)=(1/2)^x ?
s2008m [1.1K]

Answer:

The answer is c


Step-by-step explanation:


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Suppose that events E and F are​ independent, ​P(E)equals=0.40.4​, and ​P(F)equals=0.90.9. What is the Upper P left parenthesis
Dominik [7]

Answer:

The probability of E and F is 0.367236 ≅ 0.367

Step-by-step explanation:

* Lets study the meaning independent probability  

- Two events are independent if the result of the second event is not

  affected by the result of the first event

- If A and B are independent events, the probability of both events  

 is the product of the probabilities of the both events

- P (A and B) = P(A) · P(B)

* Lets solve the question  

- There are two events E and F

- E and F are independent

- P(E) = 0.404

- P(F) = 0.909

∵ Events E and F are independent

- To find P(E and F) find the product of P(E) and P(F)

∴ P (E and F) = P(E) · P(F)

∵ P(E) = 0.404

∵ P(F) = 0.909

∴ P(E and F) = (0.404) · (0.909) = 0.367236 ≅ 0.367

* The probability of E and F is 0.367236 ≅ 0.367

8 0
3 years ago
A pharmacist receives a shipment of 21 bottles of a drug and has three of the bottles tested. If five of the 21 bottles are cont
blagie [28]

Answer:

The probability is 0.8722

Step-by-step explanation:

There are 21 bottles

5 of them are contaminated.

there are 21 - 5 = 16 non-contaminated bottles.

So, if we grab a bottle at random, the probability that this bottle is contaminated will be equal to the quotient between the number of contaminated bottles and the total number of bottles, this is:

p = 5/21

Now we want to find the probability that, for 3 tested bottles, that less than two (0 or 1 ) are contaminated.

Let's see each case on its own.

0 bottles:

The probability of getting a non-contaminated bottle in the first try is equal to the quotient between the number of non-contaminated bottles and the total number of bottles, this is:

p₁ = 16/21

For the second bottle is the same, but because one non-contaminated bottle was drawn before, now there are 15 non-contaminated bottles and 20 bottles in total, so now the probability is:

p₂ = 15/20

and similarly, for the third bottle the probability is:

p₃ = 14/19

The joint probability is the product of the individual probabilities, we get:

P = p₁*p₂*p₃ = (16/21)*(15/20)*(14/19) = 0.4211

Now the case that one bottle is contaminated.

Let's assume that the first one is contaminated.

The probability of getting a contaminated bottle in the first draw is equal to the quotient between the number of contaminated bottles and the total number of bottles, so:

p₁ = 5/21

For the second bottle, we want a non-contaminated one, there are 16 non-contaminated bottles and 20 bottles left, so here the probability is:

p₂ = 16/20

and for the third bottle we have the probability:

p₃ = 15/19

The joint probability is:

p = p₁*p₂*p₃ = (5/21)*(16/20)*(15/19)

Also notice that we only looked at the case where the first bottle is contaminated, we also have the case where the second one is contaminated and the case where the third one is  contaminated, so there are 3 permutations, then the probability of having one contaminated bottle is:

Q = 3*p = 3*(5/21)*(16/20)*(15/19) = 0.4511

Then the probability of having less than two contaminated bottles is:

probability = P + Q = 0.4211 + 0.4511 = 0.8722

8 0
3 years ago
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