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3 years ago

What is one half times 10

Mathematics

2 answers:

lys-0071 [83]3 years ago

7 0

That would be 5, all you need to do is divide by 2 or mltiply by 0.5 to get half of a number

ivolga24 [154]3 years ago

5 0

The answer is 5. if you have 10 and take away half, you have 5.

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The function f(t) = 20 sin (pi over 5t) + 12 models the temperature of a periodic chemical reaction where t represents time in h

gregori [183]

The answer for the exercise shown above is the second option, which is: Maximum: 32°; minimum: −8°; period: 10 hours.
The explanation is shown below:
 You can make a graph of the function given in the problem above: f(t)=20Sin(π/5t)+12.
As you can see in the graph, the maximum point is at 32 over the y-axis, and the minimum is at -8.
The lenght of the repeating pattern of the function (Its period) is 10.

6 0

3 years ago

I need help!!!! :))))

zlopas [31]

Answer:

A=50.24

Step-by-step explanation:

Your diameter is 8, which makes the radius 4.

The area of a circle is

$A = \pi r^{2} \\A = \pi 4^{2}$

A=50.24

5 0

2 years ago

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viktelen [127]

Answer:

x = 41

y = 65

z = 107

Step-by-step explanation:

y and 65 are vertically opposite angles. Vertically opposite angles are equal.

y = 65

74 + y + x = 180

74 + 65 + x = 180

139 + x = 180

x = 180 - 139

x = 41

z is the exterior angle, whereas 66 and x are interior angles in a triangle.

Formula : -

Exterior angle = Sum of two interior angles

z = 66 + x

= 66 + 41

z = 107

6 0

3 years ago

A) -40÷5(2) B) (-2) + 3(12) ÷ 4 C) -2(3+4)

Furkat [3]

Always do brackets first

a) -40/10 = -4
b) 36/4 -2 = 7
c) -2 x 7 = -14

5 0

3 years ago

Read 2 more answers

. The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to nd

Blababa [14]

The question is:

The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find a second solution y2(x) of the homogeneous equation

x²y'' - 7xy' + 16y = 0; y1 = x^4

Answer:

The second solution y2 is

A(x^4)lnx

Step-by-step explanation:

Given the homogeneous differential equation

x²y'' - 7xy' + 16y = 0

And a solution: y1 = x^4

We need to find a second solution y2 using the method of reduction of order.

Let y2 = uy1

=> y2 = ux^4

Since y2 is also a solution to the differential equation, it also satisfies it.

Differentiate y2 twice in succession with respect to x, to obtain y2' and y2'' and substitute the resulting values into the original differential equation.

y2' = u'. x^4 + u. 4x³

y2'' = u''. x^4 + u'. 4x³ + u'. 4x³ + u. 12x²

= u''. x^4 + u'. 8x³ + u. 12x²

Now, using these values in the original equation,

x²(u''. x^4 + u'. 8x³ + u. 12x²) - 7x(u'. x^4 + u. 4x³)+ 16(ux^4) = 0

x^6u'' + 8x^5u' + 12x^4u - 7x^5u' - 28x^4u + 16x^4u = 0

x^6u'' + x^5u' = 0

xu'' = -u'

Let w = u'

Then w' = u''

xw' = -w

w'/w = -1/x

Integrating both sides

lnw = -lnx + C

w = Ae^(-lnx) (where A = e^C)

w = A/x

But w = u'

So,

u' = A/x

Integrating this

u = Alnx

Since

y2 = uy1

We have

y2 = (Alnx)x^4 = (Ax^4)lnx

Therefore, the second solution y2 is

A(x^4)lnx

6 0

3 years ago