The sign of the term in x^2 is negative so the graph will open downwards.
when x = 0 y = 1
The coordinates of the vertex are (0,1)
the maximum value of the function is 1
and the axis of symmetry ix x = 0 ( the y axis)
Answer: scalene and obtuse
Justification:
You can find the angles using the law of cosine:
c^2 = a^2 + b^2 - 2abcos(γ)
=> cos(γ) = [a^2 + b^2 - c^2] / (2ab)
1) cos(γ) = [10^2 + 11^2 - 15^2] / (2*10*11) = - 0.0181818
=> γ = arccos(-0.0181818} ≈ 91°
2) cos(α) = [b^2 + c^2 - a^2 ] / 2bc = [11^2 + 15^2 - 10^2] / (2*11*15] = 0.7454545
=> α = arccos(0.7454545) ≈ 41.8°
3) cos(β) = [a^2 + c^2 - b^2] / (2ac) = [10^2 + 15^2 - 11^2] /(2*10*15) = 0.68
=> β = arccos(0.68) ≈ 47.2°
4) Verification: 91° + 41.8° + 47.2° = 180°
5) The triangles with the three different sides are called scalenes (which you can tell with only the measures of the sides).
6) The triangles with one angle greater than 90° are called obtuse.
So, the triangle is scalene and obtuse.
Answer:
is that hindi or something.
Step-by-step explanation:
Answer:
1/3^2
Im trying to earn my brainliest..so if you don't mind :)
The other end point would be (5,-11)
