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ANEK [815]
3 years ago
12

Dennis and Connie purchased a radio for $128. Dennis paid $36 more than Connie. How much did each pay?

Mathematics
1 answer:
never [62]3 years ago
6 0

Answer:

Dennis paid $82 and Connie paid $46.

Step-by-step explanation:

We can set up an equation by putting in variables, c representing how much Connie paid. Since we know that Dennis paid $36 more, we will also factor that in the equation.

c + c + 36 = 128

Where c + 36 represents the amount Dennis paid, and 128 represents the total amount paid as given in the question. We can start by adding like terms. 2c + 36 = 128

Now, we can subtract 36 from each side,

2c + 36 - 36 = 128 - 36

2c = 92

Divide each side by two,

2c/2 = 92/2

c = 46

Now, to make sure this is correct, let's substitute our c for 46 in our equation:

46 + 46 + 36 = 128

92 + 36 = 128

128 = 128

Therefore, our equation is correct, and Dennis paid $82 while Connie paid $46.

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