Let point (x, y) be any point on the graph, than the distance between (x, y) and the focus (3, 6) is sqrt((x - 3)^2 + (y - 6)^2) and the distance between (x, y) and the directrix, y = 4 is |y - 4|
Thus sqrt((x - 3)^2 + (y - 6)^2) = |y - 4|
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
x^2 - 6x + 9 + y^2 - 12y + 36 = y^2 - 8y + 16
x^2 - 6x + 29 = -8y + 12y = 4y
(x - 3)^2 + 20 = 4y
y = 1/4(x - 3)^2 + 5
Required answer is f(x) = one fourth (x - 3)^2 + 5
Answer:
$95.17
Step-by-step explanation:




Answer:
<u>x = 6 units</u>
Step-by-step explanation:
We know that, By pythagoras theorem,
Hypotenuse2 = base2 + perpendicular2
Given, Hypotenuse = 6.5
perpendicular = 2.5
base = x
So, by putting the values,
6.52 = 2.52 + x2
42.25 = 6.25 + x2
36 = x2
Hence, <u>x = 6 units</u>
To complete the square, the second degree term must have a coefficient of 1.
Since the second degree term here has a coefficient of 4, we start by dividing each term on both sides by 4.



Now we can complete the square.
First, we need to find what number completes the square.
We take the coefficient of the first degree term, -7 in this case.
Divide it by 2 and square it. -7 divided by 2 is the fraction -7/2.
Now we square -7/2 to get 49/4.
We add 49/4 to both sides.



Answer:
1662.768 --) rounded 1662.8