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4 years ago

Please help

Mathematics

2 answers:

Sladkaya [172]4 years ago

6 0

Answer:

Step-by-step explanation:

The answer is d.

NeX [460]4 years ago

3 0

Answer:

Step-by-step explanation:

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Find the slope of a line perpendicular to each given line Y=-4/5x

dimulka [17.4K]

Answer:

5/4

Step-by-step explanation:

If a line is perpendicular to another, its slopes multiply up to -1.

So, we should write x•-4/5=-1

-4x/5=-1

x=-1•(-5/4)

x=5/4

So, we have y=5/4x+b

Slope is just the value before the x, which in this case is 5/4/.

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2 years ago

Which answer doesn't equal 64? A. 2^{6} B. 4^{3} C. 8^{2} D. 32^{2}

klemol [59]

First one is 64
second one is 64
third one is 64
so your last one is it because 32 * 32 is way higher than 64

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4 years ago

Read 2 more answers

The perimeter of a rectangular garage

OLga [1]

Divide area by width:

46/10 = 4.6 meters

Answer: 4.6 meters

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3 years ago

There are 3 green apples and 8 red apples in a basket what is the ratio of the red apples and the green to all the apples in the

VashaNatasha [74]

Answer:

The answer is 3:8 or 3 to 8

Step-by-step explanation:

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2 years ago

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

4 years ago