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Naddika [18.5K]
3 years ago
12

Which one is greater 1.02 1.29 or 1.202?

Mathematics
2 answers:
umka2103 [35]3 years ago
4 0
I think the answer you are looking for is 1.29
Radda [10]3 years ago
3 0
1.29 is the greatest
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HELP ME PLS WALLAHI HELP PLS
bija089 [108]

Answer:

first one answer is 0 second one answer is 2

4 0
2 years ago
I need both answers ​
Delvig [45]

Answer:

10mn -35m

8rs-2r^2+16r

they are in order.

7 0
2 years ago
Read 2 more answers
5x - 6 = -16 (Show work)
zysi [14]
  • <em>Answer:</em>

<em>x = - 2</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>5x - 6 = - 16</em>

<em>5x = - 16 + 6</em>

<em>5x = - ( 16 - 6)</em>

<em>5x = - 10</em>

<em>x = - 10 : 2</em>

<em>x = - 2</em>

<em>Good luck ! </em>

6 0
2 years ago
you plant 30 african violet seeds and 9 of them sprout use experimental probability to predict how many will sprout if you plant
Ostrovityanka [42]
Given that out of 30 planted seeds only 9 of the m sprouted, then:
Experimental probability =(number of occurrence of event)/(total number of trials made)
=9/30
=3/10
thus the number of seeds that will sprout given that 20 seeds we planted will be:
3/10×20
=6 seeds

8 0
3 years ago
Differentiate x^2 e^x logx
zimovet [89]

Product rule:

\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)

=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}

Power rule:

\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x

The exponential function is its own derivative:

\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x

Assuming the base of \log x is e, its derivative is

\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x

But if you mean a logarithm of arbitrary base b, we have

y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}

\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}

So we end up with

2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x

=xe^x(2\log x+x\log x+1)

8 0
3 years ago
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