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Bas_tet [7]
2 years ago
13

Question 1. When solving the equation 10 = x + 3 what should you do to both sides of the equation? o add 3 O subtract 3 O multip

ly by 3 o divide by 3​
Mathematics
2 answers:
tankabanditka [31]2 years ago
5 0

Answer:

x = 7 you gotta switch them over and subtract from the other side, bro.

Step-by-step explanation:

10 = x + 3

3 - 10 = 7

Andreyy892 years ago
4 0

Answer:

Subtract 3.

Step-by-step explanation:

x = 7

10-3 = 7

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♥It says that he adds 12$ each week, and by the end of 3 weeks he had 60. Well if you do 12*3
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He had 24$ in there before he started doing this.
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3 years ago
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Rewrite x5/6 divided by x1/6 in simplest radical form
lisabon 2012 [21]
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3 years ago
20 POINTS HELPPPPP
kiruha [24]

For this case we have the following expression:

\frac {216 ^ {n-2}} {(\frac {1} {36}) ^ {3n}} = 216

We multiply both sides by: (\frac {1} {36}) ^ {3n}

216 ^ {n-2} = 216 * (\frac {1} {36}) ^ {3n}

We divide both sides by 216:

\frac {216 ^ {n-2}} {216} = (\frac {1} {36}) ^ {3n}

To divide powers of the same base, we place the same base and subtract the exponents:

216 ^ {n-2-1} = (\frac {1} {36}) ^ {3n}\\216 ^ {n-3} = (\frac {1} {36}) ^ {3n}

Rewriting:

(6 ^ 3) ^ {n-3} = (\frac {1} {6 ^ 2}) ^ {3n}\\6 ^ {3n-9} = \frac {1} {6 ^ {6n}}\\6^{ 3n-9} * 6^{ 6n} = 1

To multiply powers of the same base, we place the same base and add the exponents:

6^{ 3n-9 + 6n} = 1\\6^{ 9n-9} = 1

We know that any number raised to zero is 1, a ^ 0 = 1.

So, for equality to be true:

9n-9 = 0\\9n = 9\\n = \frac {9} {9}\\n = 1

Answer:

n = 1

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3 years ago
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Step-by-step explanation:

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2 years ago
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Answer:

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Step-by-step explanation:

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