Answer:
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Step-by-step explanation:
Given:
mean, μ = 11 lb
Std. deviation, σ = 2.1
Let x = the weight that separates the top 5% of the crop.
The z-score is
z = (x - μ)/σ
= (x - 11)/2.1
From standard z-table for normal distribution,
P(z=1.645) = 0.95
Therefore
(x - 11)/2.1 = 1.645
x - 11 = 1.645/2.1 = 0.7833
x = 11.783
Answer: 11.8 lb (nearest tenth)
Q=2*s*L(T2-T1)/ (R2/R1)
1500000=2*30*10(275-22)/(R2/6)
1500000=600(253)/(R2/6)
1500000R2=600*253*6
1500000R2=910800
R2=910800/1500000
R2=0.6072.
JGH is equal to 150degrees because angle JGF is 30degrees 180 - 30 = 150
