Hello,
Let's x then number of students.
x is divisible by 12,15,18 thus by 180 (lcm)
x=180*k is a square
2²*3²*5*k= a square ==> k=5
x=180*5=900
Proof:
900/12=75
900/15=60
900/18=50
900=30²
If the p-value is greater than the level of significance (alpha), then you fail to reject the null hypothesis (H0). This is like saying we don't have enough evidence to reject the null hypothesis so we effectively accept it for now.
Answer is choice B) fail to reject the null hypothesis
it’s c
Because you do 5n+3 times 5n+3 and you get 25n^2+9
Answer:
hope it helps you!!!!!!!!
The probability of selecting exactly one ace is its likelihood
The probability that a five-card poker hand contains exactly one ace is 29.95%
<h3>How to determine the probability?</h3>
There are 4 aces in a standard deck of 52 cards.
The probability of selecting an ace would be:
p = 4/52
Also, there are 48 non-ace cards in the standard deck
So, the probability of selecting a non-ace after an ace has been selected is:
p = 48/51
The probability of selecting a non-ace up to the fifth selection are:
- After two cards have been selected is: 47/50.
- After three cards have been selected is: 46/49.
- After four cards have been selected is: 45/48.
The required probability is then calculated as:
P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Where n is the number of cards i.e. 5
So, we have:
P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Evaluate
P(1 Ace) = 0.2995
Express as percentage
P(1 Ace) = 29.95%
Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%
Read more about probability at:
brainly.com/question/25870256
