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andreyandreev [35.5K]
3 years ago
9

Multiple Choice Suppose y varies directly as x. if y = 5 when x=8, find y when x=64

Mathematics
1 answer:
Juliette [100K]3 years ago
6 0

Answer:

Step-by-step explanation:

y∞x

then

y=kx (with k as constant)

y=5 when x=8

⇒Putting this in the first equation

⇒5=k×8

⇒k=5/8

Now

y=? when x=64

Putting x=64 in the first equation

y=kx

⇒y=(5/8)×64

We get

y=40

Hope u understand

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6 0
3 years ago
I cant solve this can i get some help? <br> 2 cos x + √ 2 = 0
Alexandra [31]

Answer:

Step-by-step explanation:

2 cos x + √ 2 = 0

2 cos x = -√ 2

cos x = -√ 2  / 2

x = arcCos(  -√ 2  / 2 )

so to solve we have to use  "co-terminal " angles .. do you know what I'm saying?  do you understand the words coming out of my mouth :DDDDD OKay back to math and not movie lines .. :P

x = arcCos(  √ 2  / 2 )

x = 45 °

now find the "co terminal" angle that is on 45 ° but in the correct quadrant... since the  -√ 2   is negative.. we now that we go down the y axis.. but also positive on the x axis.. soooo.. that put the angle in the 4th quadrant... so this is an angle of 315° if we go in the CCW  ( counter clock wise )  direction but it's also -45°  in the CW  (clock wise )  direction

below is the table to remember the trig special angles

notice how it's  1,2,3,4    .. so it's super easy to remember.. the trig books don't show you this "trick"   :P

copy and paste this to your computer some where handy

Sin(0) = 0/2      =0  

Sin(30)= \sqrt{1}/2   = 1/2  

Sing(45) =\sqrt{2}/2 =\sqrt{2}/2  

Sin(60)=\sqrt{3}/2   = \sqrt{3}/2  

Sin(90)=\sqrt{4}/2   = 1  

Cos is exactly the same but counts backwards from 90°

Cos(90) = 0/2       = 0

Cos(60) = \sqrt{1} /2   = 1/2

Cos(45) = \sqrt{2}/2    =\sqrt{2}/2

Cos(30) = \sqrt{3}/2   =\sqrt{3}/2

Cos(0) = \sqrt{4}/2    = 1

8 0
3 years ago
TRUE OR FALSE PLEASE HELP ME IM CRYING
igomit [66]

Answer:

nope

Step-by-step explanation:

y= 12

4 0
3 years ago
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hichkok12 [17]
A^7 /4
That is the simplification
7 0
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serious [3.7K]

Answer:

Territory is the correct answer

have a great day and i hope you do well on your grades ^-^

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