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Alinara [238K]
3 years ago
14

What is the slope of the line that contains these points?

Mathematics
2 answers:
RUDIKE [14]3 years ago
8 0

-8-(-5)/8-5 = -3/3 = -1

Otrada [13]3 years ago
7 0
The slope of the line is -1.
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Please i need help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
tekilochka [14]

Answer:

limeted government or rule of law i think sorta mayby kindaa

4 0
2 years ago
1. What is the sum of 1/9, 2/3, and 5/18?<br> O A. 30<br> O B. 12/9<br> O C. 19/18<br> O D. 4/15
Serhud [2]

Answer:

C. 19/18

Step-by-step explanation:

\frac{1}{9}  +  \frac{2}{3}  +  \frac{5}{18 }  =  \frac{2}{18}  +  \frac{12}{18}  +  \frac{5}{18}  =  \frac{19}{18}

So the answer is C. 19/18

6 0
1 year ago
In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
3 years ago
Patti ran the race in 8.4 minutes. Maisha ran it in 8.04 minutes. How does the value of 4 in Maisha's time compare with the valu
anzhelika [568]

Answer:

Maisha ran the race in .36 seconds faster than Patti.

8.4 - 8.04 = .36

6 0
3 years ago
I need help with this please. i have a test on that. find the unknown length
Irina-Kira [14]
Ok, from your picture, it looks like you have a square and a right triangle next to each other

one of the definition of a square is that all 4 sides are equal, and its given to you that the square has a side length of 3
since the triangle shares a side with the square, that means that shared side has a length of 3

ok, now how about determining the unknown length x

well the base has a length of 5, but you also know that when you add the length of the square side plus x, you should get 5

3+x = 5
and you can solve for x  (subtract 3 from both sides)
x=2

now how about determining side length y
well since you know this is a right triangle, you can apply pythagorean theorem
A^2 +B^2 = C^2
where C is the hypothenuse of the triangle, or the longest side

when you substitute the known values (3 and x)
you get
3^2 + x^2 = y^2

since you already know x=2
3^2 +2^2 = y^2

and you can solve for y

any questions?
3 0
3 years ago
Read 2 more answers
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