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Amanda [17]
3 years ago
7

What are the common multiples of 18 15 12?

Mathematics
1 answer:
hichkok12 [17]3 years ago
6 0
1 and 3. Hope this helps
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A population of values has a normal distribution with μ = 158.9 μ = 158.9 and σ = 90.4 σ = 90.4 . You intend to draw a random sa
rosijanka [135]

Answer:

P_{39}=133.68    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 158.9

Standard Deviation, σ = 90.4

We are given that the distribution is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.39

P( X < x) = P( z < \displaystyle\frac{x - 158.9}{90.4})=0.39  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 158.9}{90.4} = -0.279\\\\x = 133.6784\approx 133.68  

P_{39}=133.68

133.68 separates the bottom 39% means from the top 61% means.

7 0
4 years ago
RESPOND QUICK
mrs_skeptik [129]

Answer:

A

Step-by-step explanation:

3/24=9/72        3*3=9    24*3=72      x=3

3/9=y/12         9/3=3        12/3=4      y=4

X=3 y=4

6 0
3 years ago
Parallel lines in space are coplanar.
kakasveta [241]
Coplanar lines are line witch lie on the same lie on the same plane. two parallel lines or two intersecting lines always lie in a plane. Thus, two line are coplanar, if and only if they are either parallel or intersecting. lines in three dimensional space are coplanar, only if they are not skewed lines.
3 0
4 years ago
Six hundred paving stones were examined for cracks, and 20 were found to be cracked. The same 600 stones were then examined for
spin [16.1K]

Answer:

a) probability that is cracked=1/30 (3.33%)

b) probability that is discoloured = 29/600 (4.83%)

c) probability that is cracked and discoloured =  11/600 (1.83%)

Step-by-step explanation:

assuming that each stone is equally likely to be chosen then defining the events C= the stone is cracked , D= the stone is discoloured , N= the stone is neither cracked or discoloured, then

P(C)= number of favourable outcomes/total number of outcomes = 20 stones/600 stones = 1/30 (3.33%)

P(D)= number of favourable outcomes/total number of outcomes = 29 stones/600 stones = 29/600 (4.83%)

the probability that is discoloured and cracked is P(C∩D) , where

P(C∪D)=P(C) + P(D)-P(C∩D)

and

P(C∪D)= 1- P(N)

thus

1- P(N)=P(C) + P(D)-P(C∩D)

P(C∩D)= P(N)+P(C)+P(D) -1

replacing values

P(C∩D)= P(N)+P(C)+P(D)=562/600 + 20/600 + 29/600 -1= 611/600 -1 = 11/600

thus

P(C∩D)=  11/600 (1.83%)

3 0
3 years ago
write an expression for the sequence of operations described below. add s to t, add the result to r, then raise what you have to
Kobotan [32]

Answer:

(s+t+r)^7

Step-by-step explanation:

<u>Sequential Operations </u>

Mathematical operations can be done in sequence or in batches if they are of the same type. For example, we can add many terms in one single operation, but we cannot add and multiply in one go, because there are priorities when dealing with products and sums. Same happens with powers.

In our problem we are required to perform a sequence of operations like follows

Add s to t:

s+t

Add the result to r

s+t+r

Raise what you have to the 7th power

\boxed{(s+t+r)^7}

This is the final result

6 0
4 years ago
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