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sweet [91]
3 years ago
15

Suppose you want to put a frame around the painting shown at the right. The frame will be the same width around the entire paint

ing. You have 276 in.2 of framing material. How wide should the frame be?
Mathematics
1 answer:
love history [14]3 years ago
5 0

Answer:

The frame should be 36 + 2b + 16 + 2b

Step-by-step explanation:

To solve this question, let assign 36 in x 16 in as the dimension of the painting.

276 in^2 is the area of the framing material to be used.

Let the width of the frame around the frame be "b", thus; the dimension of the frame is 36 + 2b + 16 + 2b

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if a company has 5 employees with annual saleries of $40,000, $50,000, $40,000, $60,000 and $90,000 what is the mean anulal sala
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8 0
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Which of the following is most likely the next step in the series?
saw5 [17]

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Step-by-step explanation:

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3 years ago
Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.
Nata [24]

Answer:

Step-by-step explanation:

Given the definite integral \int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx, we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}

= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} }  \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du }  \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}]  \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\

= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C

substitute u = 1-2x⁵ into the result

= \dfrac{1}{40(1-2x^5)^4} +C

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5 0
3 years ago
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