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3 years ago

Solve for x. 3/x-1 - 1/x^-1=5/x-1 Please show all work

Mathematics

2 answers:

navik [9.2K]3 years ago

5 0

3/(x-1) - 1/(x^2-1) = 5/(x-1)

Subtract 3/(x-1) from both sides

-1/(x^2-1) = 2/(x-1)

Factor x^2 - 1

-1/[(x-1)(x+1] = 2/(x-1)

Multiply by (x-1)(x+1) on both sides

-1 = 2 (x+1)

-1 = 2x + 2

Subtract 2 from both sides

-3 = 2x

Divide by 2 on both sides

-3/2 = x

Kitty [74]3 years ago

3 0

Answer:

x = -3/2

Step-by-step explanation:

$\frac{3(x+1)}{(x-1)(x+1)} - \frac{1}{(x-1)(x+1)} = \frac{5(x+1)}{(x-1)(x+1)} \\$ Find the common denominator

3(x+1) - 1 = 5(x+1) Distribute

3x + 3 -1 = 5x +5 Combine Like terms

3x + 2 = 5x + 5 Solve for x

2 = 2x +5

-3 = 2x

x = -3/2

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Help!!

Elza [17]

Answer:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

Step-by-step explanation:

Required

Which equals $x = 4$

$(a)\ 2x + 6 = 2$

Collect like terms

$2x = 2 - 6$

$2x = -4$

Divide both sides by 2

$x = -2$

$(b)\ 2x - 9 = -1$

Collect like terms

$2x = -1 + 9$

$2x = 8$

Divide both sides by 2

$x = 4$

$(c)\ -2x + 12 = 4$

Collect like terms

$-2x =- 12 + 4$

$-2x =-8$

Divide both sides by -2

$x = 4$

$(d)\ 2(x + 2) = 10$

Divide both sides by 2

$x + 2 =5$

Collect like terms

$x = 5-2$

$x = 3$

$(e)\ 2(x - 10) = -12$

Divide both sides by 2

$x - 10 = -6$

Collect like terms

$x = 10 - 6$

$x = 4$

Hence, the equations with the required solution are:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

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3 years ago

NEED HELP ASAP!!!!!!! WILL MARK CORRECT ANSWER BRAINLIEST!!!!

Ganezh [65]

Answer:

(x + 1)² + (y - 1)² = 1.5625

Step-by-step explanation:

From the picture we see:

The radius is 5 units. Each unit is .25 so the radius is 1.25.

The centre or middle M= ( -1, 1 )

Circle with centre M and radius r :

(x - xM)² + (y - yM)² = r²

xM = -1

yM = 1

r = 1.25

(x - (-1))² + (y - 1)² = (1.25)²

(x + 1)² + (y - 1)² = 1.5625

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Step-by-step explanation:

She gets $220 in an 8 hour work day.

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Read 2 more answers

Ship A receives a distress signal from the southwest, and ship B receives a distress from the same vessel from the north. At wha

Fiesta28 [93]

I've attached an image showing the coordinates of Ship A and Ship B.

Answer:

distressed vessel is located at (1, 1.5)

Step-by-step explanation:

From the image attached, we can see that;

Coordinate of ship A is (3, 4)

Coordinate of ship B is (1, 1)

Now, we are told that Ship A receives a distress signal from the southwest, and ship B receives a distress from the same vessel from the north.

This means that the distressed ship is somewhere in between ship A & B.

To solve this, we will extend the arrow line from Ship A in that same SW direction and we will do the same for ship B in the same North direction. Their point of intersection is where the distressed ship is located.

Now, if we do that, we will see that they will intersect at the point; (1, 1.5)

Thus,distressed vessel is located at (1, 1.5)

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4 years ago