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skelet666 [1.2K]
1 year ago
15

Graph the function f(x)=-3x+1.

Mathematics
1 answer:
exis [7]1 year ago
7 0

The y-intercept is (0, 1).

Substituting x=-3 yields f(x)=-\frac{1}{3}(-3)+1=2.

So, draw the line through (0, 1) and (-3, 2).

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angelo's mother put $50 on a lunch card he spends the same amount each day for lunch. what is the constant rate of change for th
Rina8888 [55]

Given that Angelo spends the same amount everyday from the amount in

the lunch card, the function of the amount remaining is a linear function.

  • The constant rate of change of the function is; <u>-5.25</u>
  • The two ordered pair used to find the constant rate of change are; <u>(1, 44.75) and (2, 39.5)</u>

Reasons:

The amount Angelo's mother put on the lunch card = $50

A possible table of values to the question is presented as follows;

\begin{tabular}{r|c|c|c|c|}Days&0&1&2&3\\Money Remaining&&44.75&39.5&\end{array}\right]

Required:

The constant rate of the function that gives the amount remaining from the

amount Angelo's mother put on his lunch card.

Solution:

  • Slope \ or \ constant \ rate \ of \ change  = \mathbf{\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}

The two ordered pair that can be used to find the slope or constant rate of change are;

(x₁, y₁) = (1, 44.75), and (x₂, y₂) = (2, 39.5)

With the above two ordered pairs, we have the constant rate of change of the function given as follows;

Constant \ rate \ of \ change\  (The \ slope) =\dfrac{39.5-44.75}{2-1} = \mathbf{ -5.25}

The constant rate of change for the function that gives the amount remaining in the lunch card is; <u>-5.25</u>

Learn more about the constant rate of change of a function here:

brainly.com/question/10007759

brainly.com/question/16644839

3 0
3 years ago
How much of a radioactive kind of ruthenium will be left after 8 hours if you start with 3,888
ziro4ka [17]

Answer:

Step-by-step explanation:

As an example, iodine-131 is a radioisotope with a half-life of 8 days. It decays by beta particle emission into xenon-131. After eight days have passed, half of the atoms of any sample of iodine-131 will have decayed, and the sample will now be 50% iodine-131 and 50% xenon-131.

50 grams to 25 grams is one half-life. 25 grams to 12.5 grams is another half-life. So, for 50 grams to decay to 12.5 grams, two half-lives, which would take 36 days total, would need to pass. This means each half-life for element X is 18 days.

7 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP ITS GEOMETRY
stiks02 [169]

Answer:

I don't realy know

Step-by-step explanation:

I think it's B

8 0
1 year ago
What is the solution of 5 = t/2 -3?
Sladkaya [172]

Answer:

t=16

Step-by-step explanation:

you have to change the numbers to get just the variable.

we start from -3.

5=t/2-3

8=t/2

(we multiply by 2 instead of dividing)

8×2=16

t=16

5 0
3 years ago
Will give brainliest
ehidna [41]

Answer:

25.047 or roughly 25.

Step-by-step explanation:

I solved it wrong the first time then i double check with wolframalpha and got the correct number.

We know that the area of the tile is 18 \sqrt{3} and it makes a triangle, we also know the base and height. In this case the base is 2\sqrt{3}^{x/12} and the height is also given which is \sqrt{3}^{\frac{x}{6} }.

Area of triangle = \frac{bh}{2},

substituting we will end up with  18 \sqrt{3}  =( 2\sqrt{3}^{x/12}  *  \sqrt{3}^{\frac{x}{6} }) / 2

Here is the tricky part \sqrt{x} = x^{\frac{1}{2} }, i totally forgot about that lol.

Simplifying: we will get  18 \sqrt{3} = 3^{\frac{x}{8} }

Now, in order to find the x, we will need to take the log of both sides.

log18\sqrt{3}  = \frac{x}{8} log3

Solving for x we end up getting:

8\frac{log18\sqrt{3} }{log3} = x

where x = 25.047.

To be honest I deserve a nobel prize not a brainliest lol.

Good question bro, take it easy.

5 0
3 years ago
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