Answer: 13
Step-by-step explanation:
If the prior population proportion is unavailable then the formula to find the sample size is given by :-
, where z* = Critical z-value
E = margin of error
Let p be the proportion of Americans who support the gun control in 2018.
As per given , we have
Confidence level = 99%
The critical z-value for 99% confidence interval is 2.576 ( BY z-table)
Margin of error : E= 0.36
Since there no prior information about the proportion of Americans who support the gun control in 2018.
So , the required sample size to estimate 99% confidence interval would be:
Hence, 13 Americans should be surveyed.
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False, 0.726mg = 0.000726
Answer:
Yes
Step-by-step explanation:
Given that your classmate suggests that the margin of error in the interval could be reduced if the confidence level were changed to 90% instead of 95%.
This is a true statement
Reason:
Confidence interval = mean±margin of error
margin of error = Critical value * Std error
Thus we have the higher the margin of error the wider the confidence interval.
And the higher the critical value the higher the margin of error.
In other words when confidence level is reduced from 95% to 90% we get reduced critical value and as a result narrower confidence interval.
True statement