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2 years ago

One leg of a right triangle measures 10 inches while the other leg measures sqrt(21) Inches . What is the length of hypotenuse ?

Mathematics

2 answers:

Sveta_85 [38]2 years ago

4 0

Answer:

$\sqrt{541} \\$ =x

Step-by-step explanation:

10^2+21^2=x^2]

100+441=x^2

541=x^2

$\sqrt{541} \\$ =x

Snezhnost [94]2 years ago

4 0

Answer:

c= 23.26 inches

Step-by-step explanation:

a^2+b^2= C^2

c=a^2+b^2=10^2+21^2=23.25941

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pshichka [43]

Answer:

(7,12),(-12,-7)

Step-by-step explanation:

x^2 + y^2 = 193

x - y = - 5

x = y - 5

(y - 5)^2 + y^2 = 193

y^2 - 10y + 25 + y^2 = 193

2y^2 - 10y + 25 = 193

2y^2 - 10y + 25 - 193 = 0

2y^2 - 10y - 168 = 0

2*(y^2 - 5y - 84) = 0 This factors into

2*( y - 12) (y + 7) = 0

y = 12

in which case x = 12 - 5 = 7

y = - 7

in which case x = -7 - 5 = - 12

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2 years ago

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pav-90 [236]

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2 years ago

A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it

natima [27]

Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, $h_o=5\ ft$

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

$h=-16t^2+vt+h_0$

Putting all the values,

$h=-16t^2+60t+5$ .....(1)

For maximum height, put

$\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s$

Put t = 1.875 in equation (1)

$h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m$

So, the maximum height reached by the ball is 61.25 m.

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2 years ago

For each 70 mm of coloured fabric Alex uses to make his curtains, he also uses 20 cm of white fabric. Express the amount of whit

Fed [463]

Answer:

20×10=200mm

70:200

70/10=7

200/10=20

7:20 is your answer in it's simplest form

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You have two cats. Each cat has a litter of K kittens. Write an expression that describes a total number of cats and kittens you

elena-14-01-66 [18.8K]

2xk=24
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2 years ago