Answer: Movement along fault line
Explanation:
Here's the remainder of the question:
Which map best predicts the likely movement of land along the fault line over thousands of years?
A transform fault is simply refered to a as a fault that occurs along the plate boundary such that the motion in such case is horizontal and ends when there's a connection with another plate boundary.
Based on the question, the map that best predicts the likely movement of land along the fault line over thousands of years will be a movement along fault line.
Answer:
Ear Damage this would affect the individuals hearing aid there by making it difficult to hear clearly
Answer:
0.153
Explanation:
We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.
So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.
ρVg = ρ'V'g + ρ"V"g
ρV = ρ'V'g + ρ"V"
Its new body volume = volume of water displaced, V = V' + V"
ρ(V' + V") = ρ'V' + ρ"V"
ρV' + ρV" = ρ'V' + ρ"V"
ρV' - ρ"V' = ρ'V" - ρV"
(ρ - ρ")V' = (ρ' - ρ)V"
V'/V" = (ρ - ρ")/(ρ' - ρ)
= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)
= (0.9988 g/cm³ ÷ 0.18 g/cm³)
V'/V" = 5.55
Since V = V' + V"
V' = V - V"
(V - V")/V" = 5.55
V/V" - V"/V" = 5.55
V/V" - 1 = 5.55
V/V" = 5.55 + 1
V/V" = 6.55
V"/V = 1/6.55
V"/V = 0.153
So, the fish must inflate its air sacs to 0.153 of its expanded body volume
Black stuff from volcanos!
Answer: I think you have to divide each level by 10 so the first level will stay the same and the rest go like this
3,500,000 divided by 10 equals 350,000
350,000 divided by 10 equals 35,000
and 35,000 divided by 10 equals 3,500
Explanation:
I don’t know if it’s correct
