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3 years ago

what is a solid figure with two congruent polygons that are bases connected with lateral faces that are rectangles

Mathematics

1 answer:

Alenkinab [10]3 years ago

6 0

Well i learned this awhile ago... Its a prism!

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2.3y +7 =-11 hehebbn

Andre45 [30]

Answer:

y=-6

Step-by-step explanation:

3y+7=-11

3y=-11-7

3y=-18

y=-18/3

y=-6

4 0

3 years ago

LAST QUESTION...ILL GIVE BRAINLESS FOR BEST EXPLANATION

Dennis_Churaev [7]

Answer:

175

Step-by-step explanation:

The circle has to = 360 degrees. 360-10=350

350/2=175

The x is halfway that's why you divide by 2.

4 0

3 years ago

Find the unknown of the following

abruzzese [7]

Step-by-step explanation:

For 4.

4b + 2b + 3b = 180°< Sum of angles of triangle >

9b = 180°

b = 180° / 9

b = 20°

4b = 4* 20° = 80°

2b = 2* 20° = 40°

3b = 3 * 20° = 60°

For 5.

x = 64° + 45° <Exterior angle of a triangle is equal to the sum of two opposite interior angles>

x = 109°

Hope it helps :)

8 0

3 years ago

Brainliest for whoever gets this right!

My name is Ann [436]

Answer:

$x=\frac{(a^2+ab)}{a-b}$

Step-by-step explanation:

So we want to make x the subject of the formula:

$a(x-b)=a^2+bx$

First, distribute the left side:

$a(x)-a(b)=a^2+bx\\ax-ab=a^2+bx$

Combine all the terms with x with it on one side. To do this, first subtract bx from both sides. The right side cancels:

$(ax-ab)-bx=(a^2+bx)-bx\\ax-ab-bx=a^2$

Remove the -ab from the left. Add ab to both sides. The left side cancels:

$(ax-ab-bx)+ab=a^2+ab\\ax-bx=a^2+ab$

Now, distribute out the x from the left side:

$ax-bx=a^2+ab\\x(a-b)=a^2+ab$

Divide both sides by (a-b). The left side cancels:

$\frac{(x(a-b))}{a-b}=\frac{(a^2+ab)}{a-b} \\x=\frac{(a^2+ab)}{a-b}$

Therefore:

$x=\frac{(a^2+ab)}{a-b}$

5 0

3 years ago

Read 2 more answers

Choose all the expressions that have 3/4 as a product.

Makovka662 [10]

The second one and the third one have a product of 3/4 hope this helps you

7 0

3 years ago