Question

Brainliest for whoever gets this right!

Answer 1

Answer:

$x=\frac{(a^2+ab)}{a-b}$

Step-by-step explanation:

So we want to make x the subject of the formula:

$a(x-b)=a^2+bx$

First, distribute the left side:

$a(x)-a(b)=a^2+bx\\ax-ab=a^2+bx$

Combine all the terms with x with it on one side. To do this, first subtract bx from both sides. The right side cancels:

$(ax-ab)-bx=(a^2+bx)-bx\\ax-ab-bx=a^2$

Remove the -ab from the left. Add ab to both sides. The left side cancels:

$(ax-ab-bx)+ab=a^2+ab\\ax-bx=a^2+ab$

Now, distribute out the x from the left side:

$ax-bx=a^2+ab\\x(a-b)=a^2+ab$

Divide both sides by (a-b). The left side cancels:

$\frac{(x(a-b))}{a-b}=\frac{(a^2+ab)}{a-b} \\x=\frac{(a^2+ab)}{a-b}$

Therefore:

$x=\frac{(a^2+ab)}{a-b}$

Answer 2

Answer:

Step-by-step explanation:

ax -ab = + bx

collect like terms

ax-bx= +ab

factorise

x(a-b)=a(a+b)

x=$\frac{a(a+b)}{a-b}$ or $\frac{a^{2} + ab}{a -b}$