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Temka [501]
3 years ago
14

A three-letter word used to show division in a word problem

Mathematics
2 answers:
Nataliya [291]3 years ago
5 0

Answer:

the answer is <u>PER</u>

Step-by-step explanation:


White raven [17]3 years ago
4 0
<span><span><u>Answer</u>
</span><span>Per


</span><u>Explanation.</u><span>
Division is the inverse of multiplication. When you want to write a division question you can use difference forms.
For example, if you want to divide y by x, you can write it as;
1) y÷x
2) Using long division of y divide by x.
3) y/x
The third option is called over or </span>per<span> and it is read as y over x.
</span></span>
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The mass, m grams, of a radioactive substance, present at time t days after first being observed, is given by the formula m=24e^
Reika [66]

Answer:

(i) The value of<em> m</em> when t = 30 is 13.2

(ii) The value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) The rate of the mass when t=50 is -0.18            

Step-by-step explanation:

(i) The <em>m</em> value when t = 30 is:

m = 24e^{-0.02t} = 24e^{-0.02*30} = 13.2

Then, the value of<em> m</em> when t = 30 is 13.2

(ii) The value of the mass when t=0 is:

m_{0} = 24e^{-0.02t} = 24e^{-0.02*0} = 24    

Now, the value of <em>t </em>is:

ln(\frac{m_{0}/2}{24}) = -0.02t

t = -\frac{ln(\frac{24}{2*24})}{0.02} = 34.7

Hence, the value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) Finally, the rate at which the mass is decreasing when t=50 is:

\frac{dm}{dt} = \frac{d}{dt}(24e^{-0.02t}) = 24(e^{-0.02t})*(-0.02) = -0.48*                            (e^{-0.02*50}) = -0.18

Therefore, the rate of the mass when t=50 is -0.18.

I hope it helps you!                  

3 0
3 years ago
Why is it important to rename 4 1/4 if you subtract 3/4 from it
zavuch27 [327]
Because 3 2/4 would be the answer when you subtract it and most teachers and/or tests want you to simplify the answer which would be 1/2 because you would divide the numerator and denominator by 2. 
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3 years ago
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