Answer:
Step-by-step explanation:
Given the equation = 
Required: To factor out 1/3;

1/3 is common to both sides;
So, 1/3 is a common factor

To solve for the value of p;
= 0




Answer:
a. 7
b 8
c 9
d 10
e 10
f 44
Step-by-step explanation:
To determine the amount of milk that David should be adding, we need to generate and expression that would relate the number of strawberries and the number of cups. From the problem statement, it is said that the number of strawberries is directly proportional to the number of cups of milk. We write it as:
X α Y where X represents the number of strawberries and Y represents the number of cups of milk
To get rid of the proportionality sign, we introduce a proportionality constant k. We calculate this by using the initial conditions given.
X = kY
at X = 14 strawberries Y = <span>2 1/2 cups of milk = 5/2 cups
14 = k(5/2)
k = 28/5
At X = 203
X = kY
203 = 28/5 (Y)
Y = 145/4 or 36 1/4 cups of milk needed</span>
c=1,200+215g
Step-by-step explanation:
so 1,200 each week so 1,200 per seven days. g is how many times they fill up the gas tank and the cost is 250 each time. So you have to multiply 215 by g and then add 1,200.