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den301095 [7]
3 years ago
9

The quotient of a number and two imcreased by five is 10 equation

Mathematics
1 answer:
morpeh [17]3 years ago
3 0

x/2 + 5 = 10

<em><u>Subtract 5 from both sides.</u></em>

x/2 = 5

<em><u>Multiply both sides by 2.</u></em>

x = 10 (This is your answer.)

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What is the sequence in this set explain the pattern. 7.5 6.25 5​
kolbaska11 [484]

Answer:

subtract 1.25

Step-by-step explanation:

You can look at this and figure out that each time they are subtracting 1.25.

8 0
3 years ago
The route to an ancient pyramid is 79 miles long.
Nostrana [21]

The route to an ancient pyramid is 79 miles long; if 20 miles is travelled each day for 3 days, the distance travelled in the fourth day would be 19 miles.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let the distance travelled in the first day be 20 miles. If the same time was travelled for 3 days, hence:

3(20) + x = 79

x = 19 miles

The route to an ancient pyramid is 79 miles long; if 20 miles is travelled each day for 3 days, the distance travelled in the fourth day would be 19 miles.

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8 0
2 years ago
Javier asks his mother how old a tree in their yard is. His mother says, "The sum of 10 and two-thirds of that tree's age, in ye
Sloan [31]

Answer:

His error is adding 10 and 2/3 before multiplying by a(age of the tree)

Step-by-step explanation:

The sum of 10 and two-thirds of that tree's age, in years, is equal to 50.

Correct equation

Sum = addition (+)

two-thirds = 2/3

The tree's age = a

10 + 2/3a = 50

2/3a = 50 - 10

2/3a = 40

a = 40 ÷ 2/3

= 40 × 3/2

= 60

a = 60 years

Javier writes the equation

(10 + two-thirds) a = 50

(10 + 2/3)a = 50

(30+2/3)a = 50

32/3a = 50

a = 50 ÷ 32/3

= 50 × 3/32

= 150/32

a = 150/32

His error is adding 10 and 2/3 before multiplying by a(age of the tree)

5 0
3 years ago
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hammer [34]

Answer:

a = -21

Step-by-step explanation:

6 0
3 years ago
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Answer:

am I supposed to join your meet with that C0DE

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2 years ago
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