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3 years ago

Can someone help me find the value of these missing angles its due in 20 minutes

Mathematics

2 answers:

dimulka [17.4K]3 years ago

8 0

Answer:

8. x=67°

9. x=55°

10. 2, 7, & 6 are 62°, 1, 4, 5, & 8 are 118°

Step-by-step explanation:

A straight line always has a degree of 180°, so knowing this, it is a simple use of subtraction to get the other angles. For 9 and 10, since the lines are parallel, the angles are the same.

Ksju [112]3 years ago

7 0

Answer:

Step-by-step explanation:

1. 118

2. 62

4. 118

5. 118

6. 62

7. 62

8. 118

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Mamont248 [21]

Answer: see proof below

<u>Step-by-step explanation:</u>

Use the Sum & Difference Identity: cos (A + B) = cos A · cos B - sin A · sin B

Recall the following from Unit Circle: cos (π/2) = 0, sin (π/2) = 1

cos (π) = -1, sin (π) = 0

Use the Quotient Identity: $\tan A=\dfrac{\sin A}{\cos A}$

<u>Proof LHS → RHS:</u>

$\text{LHS:}\qquad \qquad \dfrac{\cos \bigg(\dfrac{\pi}{2}+x\bigg)}{\cos \bigg(\pi +x\bigg)}$

$\text{Sum Difference:}\qquad \dfrac{\cos \dfrac{\pi}{2}\cdot \cos x-\sin \dfrac{\pi}{2}\cdot \sin x}{\cos \pi \cdot \cos x-\sin \pi \cdot \sin x}$

$\text{Unit Circle:}\qquad \qquad \dfrac{0\cdot \cos x-1\cdot \sin x}{-1\cdot \cos x-0\cdot \sin x}$

$=\dfrac{-\sin x}{-\cos x}$

Quotient: tan x

LHS = RHS $\checkmark$

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Answer:

The solution is given below:

Step-by-step explanation:

The computation is shown below:

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