Question

The Ksp expression for the system PbCl2(s) Pb+2(aq) + 2 Cl-(aq) is: [PbC12][Pb+2][2Cl-] [Pb+2][Cl-]2 [Pb+2][2Cl-]2 [PbCl2][Pb+2][Cl-]2 [Pb+2][2Cl-]2[PbCl2]

Answer 1

Answer:The Ksp expression for the system

$K_{sp}=[Pb^{2+}][Cl^-]^2$

Step-by-step explanation:

The $K_{sp}$ od the substance that solubility product is defined as mathematical product of concentration of dissolved ions raised to the power equal to their stoichiometric coefficient in reaction.

$A_2B_3\rightleftharpoons 2A^{3+}+3B^{2-}$

$K_{sp}=[A^{3+}]^2\times [B^{2-}]^3$

For the given system:

$PbCl_2(s)\rightleftharpoons Pb^{2+}+2Cl^-$

$K_{eq}=\frac{[PB^{2+}][Cl^-]^2}{[PbCl_2]}$

$K_{eq}\times [PbCl_2]=K_{sp}$

$K_{sp}=[Pb^{2+}][Cl^-]^2$

The Ksp expression for the system : $K_{sp}=[Pb^{2+}][Cl^-]^2$