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SpyIntel [72]
4 years ago
10

Julio sells computers at an electronics store. Let the random variable C represent the number of computers that Julio sells in o

ne week. The following table shows the probability distribution of C .
Julio earns $800 per week, with a commission of $200 per computer sold. What is the expected value of Julio’s earnings for one week?


A. $3.31
B. $662
C. $1,462
D. $2,848
E. $3,310
Mathematics
1 answer:
skelet666 [1.2K]4 years ago
5 0
I think C maybe but im not sure
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WILL MAEK BRAINLIST
Arisa [49]

Answer:

m = -6/7

b = -2

Step-by-step explanation:

m = (y2 - y1)/(x2 - x1) = (-2 - 4)/(0 - (-7)) = -6/7

y = mx + b

m = -6/7

y = -6/7 x + b

Use point (-7, 4).

4 = (-6/7)(-7) + b

4 = 6 + b

b = -2

y = -6/7 x - 2

m = -6/7

b = -2

5 0
3 years ago
Which expressions are polynomials?
Oduvanchick [21]

Answer:


Step-by-step explanation:

Definition : The expression that can have constants (like 4), variables (like x or y) and exponents (like the 2 in y^{2}), that can be combined using addition, subtraction, multiplication and division, but no division by a variable and a variable's exponents can only be 0,1,2,3,... etc. and it can't have an infinite number of terms.

1. 6 + p

Being p be a variable this equation is polynomial

2.  x – 1

Since x-1 has variable and constant so according to definition it is a polynomial

3. 8x−z3

According to definition it is a polynomial

4 .5x^{2}-x\sqrt{}

Since has root so it is not a polynomial .


6 0
3 years ago
Read 2 more answers
Anyone mind helping? 15 Points! :D
Vsevolod [243]

Answer:

(2x+8y)

(2x+2×4y)

2(x+4y)

5 0
3 years ago
Math help please question in the picture
Kazeer [188]
This took me a while but I'm pretty sure the answer is
y =  -  \frac{1}{3} x - 1
I had to review perpendicular bisectors but yeah it has to do with the midpoint and point slope formula
7 0
3 years ago
Solve the equation and show all work. 4|x + 1/3| = 20 <br> i'm kind of stuck hhh
34kurt

Absolute value is a function that takes some number and outputs the size of that number, regardless of the sign. By definition, |x|=x if x\ge0, and |x|=-x if x.

For example,

  • |2| = 2 because the input 2 is positive, so the input is unchanged;
  • |-3| = -(-3) = 3 because the input -3 is negative, so the sign is switched.

What this means for this problem is that there are two cases to consider:

  • If x+\frac13\ge0, then \left|x+\frac13\right|=x+\frac13, so that

4\left(x+\dfrac13\right)=20\implies x+\dfrac13=5\implies\boxed{x=\dfrac{14}3}

  • On the other hand, if x+\frac13, then \left|x+\frac13\right|=-\left(x+\frac13\right), so

-4\left(x+\dfrac13\right)=20\implies x+\dfrac13=-5\implies\boxed{x=-\dfrac{16}3}

6 0
4 years ago
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