Question

The figure shown has a parallelogram on top and a rectangle below it:

Answer 1

Answer:

The area of the figure is $962.48\ in^{2}$

Step-by-step explanation:

we know that

The area of the figure is equal to the area of parallelogram plus the area of rectangle

Step 1

Find the area of rectangle

The area of rectangle is equal to

$A=LW$

we have

$L=42.4\ in$

$L=10.5\ in$

substitute

$A=42.4*10.5=445.2\ in^{2}$

Step 2

Find the area of parallelogram

The area of parallelogram is equal to

$A=bh$

we have

$b=42.4\ in$

$h=12.2\ in$

substitute

$A=42.4*12.2=517.28\ in^{2}$  

step 3

Find the area of the figure

$445.20\ in^{2}+517.28\ in^{2}=962.48\ in^{2}$

Answer 2

The total area of the figure should be 962.48 square inches