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Assoli18 [71]
4 years ago
6

Can you solve these problems?Worth-10 points

Mathematics
1 answer:
inn [45]4 years ago
3 0
12, 72, 81, 36, 50, 12, answers for bottom row.

45, 20, 42, 36, 30, 9 answers for top row.
You might be interested in
Victor has 2 fraction models.Each is divided into equal sized sections the models are shaded to represent the same fraction.Mode
QveST [7]

Answer:

Model B has 6 shaded sections

Step-by-step explanation:

The question is not complete. The complete question should be in the form:

Victor has 2 fraction models. Each is divided into equal sized sections the models are shaded to represent the same fraction. Model A is divided into 6 sections and 3 sections are shaded. Model B is divided into 12 sections. What do you know about the number of sections shaded in Model B? Explain your answer.

Solution:

The fraction modeled by model A is given by the ratio of shaded sections to  the total number of sections.

That is Fraction of model A = number of shaded sections / total number of sections.

Hence:

Fraction of model A = 3 / 6

Since model B and Model A are equivalent, the number of shaded sections in Model A is given by:

number of shaded sections in model B/ total number of sections in model B =  Fraction of model A

number of shaded sections in model B / 12 = 3 / 6

number of shaded sections in model B = 12 * 3/6

number of shaded sections in model B = 6

8 0
3 years ago
The number 2 is chosen to start a LADDER diagram to find the prime factorization of 66. What other numbers can be used to start
leonid [27]
6 and 11 and 3 and 22.
The order of the diagram may look different however, the prime factors are the same.
6 0
4 years ago
A rectangle is 3 cm long and 2 cm wide
Nimfa-mama [501]

Answer:

Perimeter = 100mm

Area = 60mm

Step-by-step explanation:

P= (3x2) + (2x2) =10cm

10mm to 1cm

10cm x 10 = 100mm

A= b x h

= 3 x 2

=6cm

6x10=60mm

7 0
3 years ago
Greatest common factor of 4ax^2+4ax+4a
Rina8888 [55]

Simplifying

4AX2 + 4AX + 4A = 0

Reorder the terms:

4A + 4AX + 4AX2 = 0

Solving

4A + 4AX + 4AX2 = 0

Solving for variable 'A'.

Move all terms containing A to the left, all other terms to the right.

Factor out the Greatest Common Factor (GCF), '4A'.

4A(1 + X + X2) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'A' equal to zero and attempt to solve:

Simplifying

A = 0

Solving

A = 0

Move all terms containing A to the left, all other terms to the right.

Simplifying

A = 0

Subproblem 2

Set the factor '(1 + X + X2)' equal to zero and attempt to solve:

Simplifying

1 + X + X2 = 0

Solving

1 + X + X2 = 0

Move all terms containing A to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + X + -1 + X2 = 0 + -1

Reorder the terms:

1 + -1 + X + X2 = 0 + -1

Combine like terms: 1 + -1 = 0

0 + X + X2 = 0 + -1

X + X2 = 0 + -1

Combine like terms: 0 + -1 = -1

X + X2 = -1

Add '-1X' to each side of the equation.

X + -1X + X2 = -1 + -1X

Combine like terms: X + -1X = 0

0 + X2 = -1 + -1X

X2 = -1 + -1X

Add '-1X2' to each side of the equation.

X2 + -1X2 = -1 + -1X + -1X2

Combine like terms: X2 + -1X2 = 0

0 = -1 + -1X + -1X2

Simplifying

0 = -1 + -1X + -1X2

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

Solution

A = {0}

3 0
3 years ago
Read 2 more answers
Help plz plzzzzzzzzzzz ASAP
hjlf

Answer:

This is because the four triangles formed are all identical to each other.

7 0
3 years ago
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