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Sergio039 [100]
3 years ago
5

Find the value of k for which the point (1, -2) lies on the graph of the

Mathematics
2 answers:
atroni [7]3 years ago
7 0

Answer:

k= -5

Step-by-step explanation:

When x=1 and y= -2,

x-2y+k=0

1 -2(-2)+ k=0

1+4+k=0

5+k=0

k= -5

vovangra [49]3 years ago
4 0

Answer:

k = - 5

Step-by-step explanation:

Since point (1, - 2) lie on the line x - 2y + k = 0.

So, plug x = 1 & y = - 2 in the given equation of line, we find:

1 -  2( - 2) + k = 0 \\ 1  + 4 + k = 0 \\ 5 + k = 0 \\  \implies  \huge \purple{ \boxed{\: k =  - 5}}

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Answer:

It should be y=4x-7

Step-by-step explanation:

M is the slope meaning Δx over Δy or rise over run

So if you look at (2,2) and count up to (3,6) the rise is 4 and the run is 1 meaning the slope is 4.

B is the y- intercept so then it would just be -7.

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Korolek [52]

Answer:

The answer is

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Step-by-step explanation:

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From the question the point is (-2,-7) and slope 3 is

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Hope this helps you

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