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Ipatiy [6.2K]
3 years ago
11

The point a is located on the y-axis, 6 units above the x-axis. what are the coordinates of point a?

Mathematics
1 answer:
Sonja [21]3 years ago
8 0

b. (0,6)

It says point lies on the y-axis which means that the x-coordinate is 0 and y-coordinate is given as 6.

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10+(−3.5)×2+(−9)÷(−3)
Zepler [3.9K]

Answer:

6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

10 + (-3.5) × 2 + (-9) ÷ (-3)

<u>Step 2: Evaluate</u>

  1. Multiply:                    10 - 7 + (-9) ÷ (-3)
  2. Divide:                       10 - 7 + 3
  3. Subtract:                   3 + 3
  4. Add:                           6
6 0
3 years ago
Read 2 more answers
Y=2x+8 Find y, if x is 2
Marysya12 [62]
First simplify the equation with the given information. 2(2) = 4, so the equation is now y = 4+8. Simplify further. 4+8 = 12, so y = 12.
Hope that helped you.
5 0
3 years ago
Which of the following represents this function written in intercept form
Brilliant_brown [7]

Answer:

v=2(x - 1)(x-6)=2(x²-6x-x+6)=12x²-12x-2x+12

v = 12x²-14x+12  standard form

Step-by-step explanation:

3 0
3 years ago
What is the value of x in the equation 3 minus 2 x = negative 1.5 x?
Lilit [14]

Answer:

the answer is 6

Step-by-step explanation:

5 0
3 years ago
What is the slope of the line that passes through the points (8,-8) and (5,-1)?
dezoksy [38]

Hey there!

  • Answer :

\sf{ \purple{ \boxed{\bold{m =  -  \dfrac{7}{3} }}}}

\\

  • Explanation :

We are given the points \sf{P_1(\overbrace{ \blue{8}}^{\blue{x_1}} ,\underbrace{\orange{-8}}_{ \orange{y_1}}) \: and \: P_2(\overbrace{ \green{5}}^{\green{x_2}} ,\underbrace{\red{-1}}_{\red{y_2} })} . To find the slope \sf{\purple{m}} of such a line, we use the slope formula which is the following:

\sf{ \purple{m} }=  \dfrac{\Delta y}{\Delta x}  =  \dfrac{ \red{y_2} - \orange{y_1}}{ \green{x_2 }- \blue{x_1}}

\\

⇢Now, by plugging in our values, we get :

\sf{ \purple{m}} =  \dfrac{ \red{ - 1} -  \orange{( - 8)}}{ \green{5} \:   -  \:  \blue{8}}  =  \dfrac{ \:  \: 7 \: }{ -  3 \: }  \\  \\  \implies \sf{ \purple{ \boxed{m =  -  \dfrac{7}{3} }}}

Therefore, the slope of the line is \sf{ \purple{ \boxed{m =  -  \dfrac{7}{3} }}}

8 0
2 years ago
Read 2 more answers
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