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goldfiish [28.3K]

4 years ago

8

What is a estimate of 7/10 times 16 uses a benchmark fraction

2 answers:

kogti [31]4 years ago

7 0

7/10 is 0.7
0.7 x 16 yields 11.2
11.2 is also 11 1/5
or 56/5

Annette [7]4 years ago

6 0

The answer is 11 1/5

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A law firm is going to designate associates and partners to a big new case. The daily rate charged to the client for each associ

andrew11 [14]

Answer:

there were 2 partners and 4 associates

Step-by-step explanation:

at 1300 per partner if you hire 2 thats 1300 x 2 = 2600

thrn 4 associates at 400 each 400 x 4 = 1600

now add 2600 + 1600 = 4200

6 0

4 years ago

Find the missing value to the nearest hundredth cos___= 7/18

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Let
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the answer is
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4 years ago

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tigry1 [53]

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5 0

4 years ago

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how do I set up this word problem: I have 88 pieces of gum, I gave 4 pieces each to all my class mates, I have 8 pieces left, ho

NeTakaya

There are 20 people in the class room.

One way I set this word problem up is by using the equation 88-4x=8. X would stand for the amount of classmates in the class, 88 would stand for your total pieces of gum and 8 would stand for the remaining pieces left.

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3 0

3 years ago

The cross-sectional areas of a right pyramid and a right cylinder are congruent. The right pyramid has a height of 10 units, and

Ilia_Sergeevich [38]

Answer:

The volume of the cylinder is 2.1 times the volume of the pyramid

Step-by-step explanation:

step 1

Find the volume of the pyramid

we know that

The volume of a right pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the base of pyramid

H is the height of the pyramid

we have

$H=10\ units$

substitute

$Vp=\frac{10}{3}B\ units^{3}$

step 2

Find the volume of the right cylinder

we know that

The volume of right cylinder is equal to

$V=BH$

where

B is the area of the base of cylinder

H is the height of the cylinder

we have

$H=7\ units$

substitute

$Vc=7B\ units^{3}$

step 3

Compare the volumes

we know that

The area of the base both figures are congruent

Find the ratio of their volumes

$\frac{Vp}{Vc}$

substitute

$\frac{Vp}{Vc}=\frac{(\frac{10}{3}B)}{7B}$

Simplify

$\frac{Vp}{Vc}=\frac{10}{21}$

$21Vp=10Vc\\\\Vc=2.1Vp$

therefore

The volume of the cylinder is 2.1 times the volume of the pyramid

7 0

3 years ago

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