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KonstantinChe [14]

3 years ago

11

To Baker’s plus their contents have a mass of 180.4 g the total mass of the contents is 56.8 g each Baker has the same mess righ

t and solve an equation to find the mass of one bigger

1 answer:

yKpoI14uk [10]3 years ago

4 0

Yes because the guy

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Jill walked 6 blocks. This was 25% of her walk. How far was Jill's walk? A. 14 blocks B. 30 blocks C. 12 blocks D. 24 blocks

Gnoma [55]

6 is a quarter of her walk ... there are 4 quarters in a whole (6x4) = 24

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3 years ago

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What is the equation of the line h Th ya has a y intercept of (0,-3) and passes through the point (-9,-9)

Nikolay [14]

Answer:

The line equation is given as: 3 y = 2 x - 9

Step-by-step explanation:

Here, Y intercept is at point ( 0.-3)

So, at x = 0, y = -3

or, C = -3

Also, the point on the equation line is (x,y) = (-9,-9)

Now, by <u>SLOPE INTERCEPT FORM</u> of a line equation,we get:

y = m x + C : m = slope of line ......... (1)

So, substituting the values of C and (x,y) , we get:

-9 = m (-9) + (-3)

or, -9 + 3 = - 9 m

or, m = -6/-9 = 2/3

or, m = 2/3

Now, substitute the value of m back in to the line equation (1)

$y = m x + C \implies y = (\frac{2}{3}) x - 3\\\implies 3y = 2x - 9$

Hence, the line equation is given as: 3 y = 2 x - 9.

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3 years ago

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Novay_Z [31]

Answer:

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3 years ago

Please help will mark Brainly

iris [78.8K]

The answer is D. For every week, she is giving away 10 pencils which means Mrs. Doyal is removing pencils from the 150 pencils she already has by “-10x”. Hope this helps c:

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3 years ago

Given a triangle JLM with vertices J(-4,3), L(-2,7), and M(2,7). What would the coordinates be if it was reflected across the li

topjm [15]

Answer: M'(2, - 5), L'(-2, -5), j'(-4, - 1)

Step-by-step explanation:

When we do a reflection over a given line, the distance between all the points (measured perpendicularly to the line) does not change.

The line is y = 1.

Notice that a reflection over a line y = a (for any real value a) only changes the value of the variable y.

Let's reflect the points:

J(-4, 3)

The distance between 3 and 1 is:

D = 3 - 1 = 2.

Then the new value of y must also be at a distance 2 of the line y = 1

1 - 2 = 1

The new point is:

j'(-4, - 1)

L(-2, 7)

The distance between 7 and 1 is:

7 - 1 = 6.

The new value of y will be:

1 - 6 = -5

The new point is:

L'(-2, -5)

M(2,7)

Same as above, the new point will be:

M'(2, - 5)

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3 years ago