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3 years ago

13

Josie bought a new mirror. The mirror has 5 sides. What is the shape of the mirror?

2 answers:

yuradex [85]3 years ago

8 0

If Josie bought a mirror with 5 sides it would be a pentagon

Citrus2011 [14]3 years ago

3 0

Hello!

I believe the mirror is a Pentagon.

I hope it helps!

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Which ordered pairs in the form (x, y)(x, y) are solutions to the equation

kap26 [50]

The answer is (-1,-7) because you are pluging it in -1 is x and -7 is y. so 7×-1=-7 and 5×-7 = -35 so -7 minus -35 =28

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3 years ago

It's possible to build a triangle with side lengths of 3.3, and 9<br> A. True<br> B. False

mario62 [17]

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2 years ago

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3 years ago

John ran 6 2/3 miles last week he ran 1 1/3 miles each day how many days did he run

Murljashka [212]

$6\frac{2}{3} = \frac{3(6) + 2}{3} = \frac{20}{3} miles$

$1\frac{1}{3} = \frac{3(1) + 1}{3} = \frac{4}{3} miles/day$

$\frac{20}{3} miles$ ÷ $\frac{4}{3} miles/day$

= $\frac{20(miles)}{3}$ * $\frac{3(days)}{4 (miles)}$

= $\frac{20(3) days}{3(4)} = \frac{20 days}{4} = 5 days$

Answer: 5 days

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3 years ago

Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

5 0

3 years ago