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3 years ago

Josie bought a new mirror. The mirror has 5 sides. What is the shape of the mirror?

Mathematics

2 answers:

yuradex [85]3 years ago

8 0

If Josie bought a mirror with 5 sides it would be a pentagon

Citrus2011 [14]3 years ago

3 0

Hello!

I believe the mirror is a Pentagon.

I hope it helps!

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CD is perpendicular to AB and passes through point C5, 12).

Aleksandr-060686 [28]

Answer:

x intercept of CD = 17

Step-by-step explanation:

We are given a line AB with its end coordinates. and Another line segment CD which is perpendicular to AB. We have the coordinates of C , and we are asked to find the x intercept of line CD.

For that we need to find the equation of CD

we have coordinates of C , and hence if we have slope of CD we can find equation of CD

Slope of CD can be determine with the help of slope of AB as CD⊥ AB

So, the slope of CD $mCD = -\frac{1}{mAB}$

Hence we start from determining slope of AB

slope is given as

$m= \frac{y_2-y_1}{x_2-x_1}$

$m= \frac{14-(-3)}{7-(-10)}=\frac{17}{17}=1$

Hence $mAB=1$

There fore $mCD=-1$

(∵ Product of Slopes of two perpendicular lines is always -1)

Now we find the equation of CD with the help of slope -1 and coordinates of C(5,12)

$m=\frac{y-y_1}{x-x_1}$

$-1=\frac{y-12}{x-5}$

$-x+5=y-12$

$y=-x+17$

Hence we have our equation , now in order to find the x intercept we keep y = 0 in it and solve for x

$0=-x+17$

$x=17$

Hence the x intercept is 17

8 0

3 years ago

Pls help I need a good grade I’ll brainlest

expeople1 [14]

Answer:

Step-by-step explanation:

3 0

3 years ago

ДОПОМОЖІТЬ, БУДЬ ЛАСКА !!!! МАТЕМАТИКА !!!!!!!!

ivann1987 [24]

Plot a point at the Y-Intercept of -1 and Plot another point at the X-intercept of 1 and the DIGITS graphing tool should make a line from there

6 0

3 years ago

PLEASE HELP I NEED HELP WITH THIS ASAP. PLEASE show work, thank you. Will give branliest

d1i1m1o1n [39]

If the slope is 5 perpendicular would be -1/5 just flip the slope around

3 0

3 years ago

Use Cramer's Rule to solve the following system: –2x – 6y = –26 5x + 2y = 13

andriy [413]

$\bf \begin{cases}
-2x-6y&=-26\\
\quad 5x+2y&=13
\end{cases}\stackrel{\textit{determinant of the coefficients}}{D=
\begin{bmatrix}
-2&-6\\5&2
\end{bmatrix}}\implies (-4)-(-30)
\\\\\\
D=-4+30\implies \boxed{D=26}\\\\
-------------------------------\\\\$

$\bf x=\cfrac{D_x}{D}\implies x=\cfrac{
\begin{bmatrix}
\boxed{-26}&-6\\\\ \boxed{13}&2
\end{bmatrix}}{D}\implies x=\cfrac{(-52)-(-78)}{26}
\\\\\\
x=\cfrac{-52+78}{26}\implies x=\cfrac{26}{26}\implies \boxed{x=1}\\\\
-------------------------------\\\\
y=\cfrac{D_y}{D}\implies y=\cfrac{
\begin{bmatrix}
-2&\boxed{-26}\\\\ 5&\boxed{13}
\end{bmatrix}}{D}\implies y=\cfrac{(-26)-(-130)}{26}
\\\\\\
y=\cfrac{-26+130}{26}\implies y=\cfrac{104}{26}\implies \boxed{y=4}$

4 0

3 years ago