Answer:
question 2 is true
question 3 is false
Step-by-step explanation:
The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
I don't think they are equivalent. try it yourself
X-5= 20
x-5= -20
Absolute value makes a negative positive, so when you are solving x-5 could have been 20 originally or -20 originally. Solve for both.
Answer:
D) 12
Step-by-step explanation:
divide each term by -8 and simplify
-8/-8x=-96/-8
x=12
