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Sidana [21]
2 years ago
13

A garden has a length of 90 feet and a width of 60 feet. what is the area of the garden in square yards? use 1 yard = 3 feet.

Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
7 0
You just need to multiply
90 \times 60  \div 3
then divide by 3
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In the data set below, what is the interquartile range?
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558 cm^3

Step-by-step explanation:

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Find 10 partial sums of the series. (round your answers to five decimal places.) ∞ 15 (−4)n n = 1
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Given

\Sigma_{n=1}^\infty15(-4)^n

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S_1=\Sigma_{n=1}^{1}15(-4)^n=15(-4)=\bold{-60} \\  \\ S_2=\Sigma_{n=1}^{2}15(-4)^n=\Sigma_{n=1}^{1}15(-4)^n+15(-4)^2 \\ =-60+15(16)=-60+240=\bold{180} \\  \\ S_3=\Sigma_{n=1}^{3}15(-4)^n=\Sigma_{n=1}^{2}15(-4)^n+15(-4)^3 \\ =180+15(-64)=180-960=\bold{-780} \\  \\ S_4=\Sigma_{n=1}^{4}15(-4)^n=\Sigma_{n=1}^{3}15(-4)^n+15(-4)^4 \\ =-780+15(256)=-780+3,840=\bold{3,060} \\  \\ S_5=\Sigma_{n=1}^{5}15(-4)^n=\Sigma_{n=1}^{4}15(-4)^n+15(-4)^5 \\ =3,060+15(-1,024)=3,060-15,360=\bold{-12,300}

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The rest of the partial sums can be obtained in similar way.
7 0
3 years ago
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