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olga2289 [7]
3 years ago
15

Consider the solid s described below. the base of s is the region enclosed by the parabola y = 5 - 5x2 and the x-axis. cross-sec

tions perpendicular to the x-axis are isosceles triangles with height equal to the base. find the volume v of this solid.
Mathematics
1 answer:
kumpel [21]3 years ago
3 0
<span>Consider the solid s described below. the base of s is the region enclosed by the parabola y = 5 - 5x2 and the x-axis. cross-sections perpendicular to the x-axis are isosceles triangles with height equal to the base. find the volume v of this solid.</span>
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One cake feeds 14 people. Use a proportion to find how many cakes must be purchased to feed 60 people.
katrin2010 [14]

Answer:

5 cakes


hope it helps

Step-by-step explanation:

if one cake feed 14 people and you are tying to fine out how many cakes you need to feed 60 people you would have to divide 60 by 14

1 cake = 14 people

? cakes = 60 people

60 ÷ 14 = 4.28

so in order to have enough for 60 people you need to round so you would need 5 cakes

to check you answer you can multiply 5 by 14 and you answer should be the amount of people

5 x 14 = 70

why  cant it be 4? well because if you buy 4 cakes there wont be enough for 60 people and to make sure it wont be enough you can multiply 4 x 14

4 x 14 = 56

so 4 cakes only feeds 56 people so that is why your answer is 5 cakes are needed



8 0
4 years ago
Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15.
charle [14.2K]
Hi,

Sorry i don't understand you "determine the sigma notation of the sum for term 4 through term 15" 
a_1=4\\&#10;&#10;a_2=-12=4*(-3)\\&#10;&#10;a_3=36=(-12)*(-3)=4*(-3)^2&#10;

a_4=4*(-3)^3\\&#10;&#10;a_5=4*(-3)^4\\&#10;&#10;...&#10;&#10;a_{15}=4*(-3)^{14}\\&#10;&#10;&#10;\sum_{i=4}^{15}a_i\\&#10;&#10;=a_4+a_5+...+a_{15}\\&#10;=4*(-3)^3 + 4*(-3)^4+...+4*(-3)^{14}\\&#10;=4*(-3)^3*(1+(-3)+(-3)^2+(-3)^3+...+(-3)^{11}\\&#10;&#10;=4*(-3)^3* \dfrac{(-3)^{12}-1}{(-3-1)} \\&#10;&#10;=4*(-27)* \dfrac{3^{12}-1}{(-4)}\\&#10;&#10;=27*(531441-1)\\&#10;&#10;=14348880&#10;


5 0
3 years ago
Read 2 more answers
50-20 = 30
shusha [124]
You did everything correctly! I did it myself...all of your subtraction is correct, then I added the answers together and I got 51. Where you trying to get another answer?
4 0
4 years ago
Read 2 more answers
Value of x in the solution to the system of equations.<br> 6x+3y=13<br> 3x-y=4
just olya [345]
The two easiest ways to solve a system of equations (in my opinion) are to add the equations together while getting rid of a variable, or solving for a variable in one equation and plugging it into another. The latter is the method I will use.

3x - y = 4 (solve for y)
3x = 4 + y
3x - 4 = y
y = <span>3x - 4 </span>

Now we can plug y into the other equation:
<span>6x + 3y = 13
</span>6x + 3(<span>3x - 4) = 13
</span>6x + 9<span>x - 12 = 13
</span>15x = 25
x = 25/15
x = 5/3
The answer is x = 5/3

If you ever needed to find y as well, you can plug this into either equation to find y.
3x - y = 4
<span>3(5/3) - y = 4
</span>5 - y = 4
y = 1
3 0
3 years ago
Will someone please explain how to do
MrRissso [65]
Distribute the negative first -7c+18-2>0
simplify -7c+16>0
subtract 16 both sides -7c>-16
divide by -1
MOST IMPORTANT PART
when you divide both sides by -1, you HAVE to change the greater/less than sign
so -7c>-16 becomes 7c<16
now divide by 7
c<16/7
I hope you don't yet want to graph it, because graphing is something that's a bit harder to show here

6 0
3 years ago
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