$\bf \textit{difference and sum of cubes}
\\\\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 
\\\\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\\\\
-------------------------------\\\\
64g^3+8\implies 4^3g^3+8\implies (4g)^3+2^3
\\\\\\
(4g+2)[(4g)^2-(4g)(2)+2^2]\implies (4g+2)[(4^2g^2)-8g+4]
\\\\\\
(4g+2)(16g^2-8g+4)$

3 0

3 years ago

Someone help me with this !!!

charle [14.2K]

Answer:

150°

Step-by-step explanation:

to find the individual angle of a REGULAR dodecagon (which means that all sides are equal), you'd use the equation I(individual angle)= (n-2)×180/n

N is number of sides. The number of sides on a dodecagon is 12. So, substitute N for 12

I= (12-2)×180/12 which simplifies to 10×180/12

10×180= 1800

1800/12 = 150

so, an individual interior angle of a dodecagon is 150°

6 0

3 years ago