Answers:
8. 12x+3= 27
move 3 to the other side , sign changes from +3 to -3
12x+3-3=27-3
12x= 24
divide by 12 for both sides
12x/12=24/12
x= 2
9. 6(y-10)=42
mutiply the bracket by 6
(6)(y)(6)(-10)= 6y-60
6y-60= 42
move -60 to the other side, sign changes from -60 to +60
6y-60+60=42+60
6y=102
divide by 6
6y/6=102/6
y=17
10. 9x-2=4x+13
move +4x to the other side
9x-4x-2= 4x-4x+13
5x-2= 13
5x-2+2= 13+2
5x= 15
divide by 5 for both sides
5x/5= 15/5
x= 3
11. 4/3y+5/2y= 1
find the common denominator for both of the fractions which is 6.
Mutiply by 2 for 4/3y .
4(2)/3(2)y=8/6y
Mutiply by 3 for 5/2y
5(3)/2(3y)= 15/6y
8/6y+15/6y= 23/6y
23/6y= 1
Mutiply both sides by 6/23
23/6y(6/23)= 1 (6/23)
Cross out 6 and 6 , divide by 6 and then becomes 1.
Cross out 23 and 23, divide by 23 and then becomes 1.
1*1*y=y
y= 6/23
<span> A. x²+2 - a polynomial
B.(x⁸-2)/(x⁻²+3) rational function
C. 7x⁷-2x⁻⁴+3 (It has negative value of exponent, so it cannot be a polynomial.)
D.x^x-1 (x is an exponent it cannot be a polynomial)</span>
Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,
xz_007 [3.2K]
The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.
<h3>How to determine the range of a function?</h3>
Given: 12x + 6y = 24
Here x stands for the input and y stands for the output
Replacing y with f(x)
12x + 6f(x) = 24
6f(x) = 24 - 12x
f(x) = (24 - 12x)/6
Domain = {-4, 0, 5}
Put the elements of the domain, one by one, to estimate the range
f(-4) = (24 - 12((-4))/6
= (72)/6 = 12
f(0) = (24 - 12(0)/6
= (24)/6 = 4
f(5) = (24 - 12(5)/6
= (-36)/6 = -6
The range exists {12, 4, -6}
Therefore, the correct answer is option c. {12, 4, -6}.
To learn more about Range, Domain and functions refer to:
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X +(-5y)= 13
-x+ 9y =(-17)
0+<u>4y</u>=<u>-4</u>
4 4
y=1
x+-5(1)=13
x-5=13
+5 <u>+5
</u> x=18
y=1
