$20 because 10% of 40 is 10 and the price now is 40 so 2 years before would have been 20
Answer:
![dAB=10\ units](https://tex.z-dn.net/?f=dAB%3D10%5C%20units)
Step-by-step explanation:
we know that
The <u>distance formula</u> is derived by creating a triangle and using the Pythagorean theorem to find the length of the hypotenuse. The hypotenuse of the triangle is the distance between the two points
The formula to calculate the distance between two points is equal to
![d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28y2-y1%29%5E%7B2%7D%2B%28x2-x1%29%5E%7B2%7D%7D)
we have
A(1, 1) and B(7, −7)
Let
(x1,y1)=A(1, 1)
(x2,y2)=B(7, −7)
substitute the given values in the formula
![dAB=\sqrt{(-7-1)^{2}+(7-1)^{2}}](https://tex.z-dn.net/?f=dAB%3D%5Csqrt%7B%28-7-1%29%5E%7B2%7D%2B%287-1%29%5E%7B2%7D%7D)
![dAB=\sqrt{(-8)^{2}+(6)^{2}}](https://tex.z-dn.net/?f=dAB%3D%5Csqrt%7B%28-8%29%5E%7B2%7D%2B%286%29%5E%7B2%7D%7D)
![dAB=\sqrt{64+36}](https://tex.z-dn.net/?f=dAB%3D%5Csqrt%7B64%2B36%7D)
![dAB=\sqrt{100}](https://tex.z-dn.net/?f=dAB%3D%5Csqrt%7B100%7D)
![dAB=10\ units](https://tex.z-dn.net/?f=dAB%3D10%5C%20units)
The area of square is
square units
<h3><u>Solution:</u></h3>
Given that square has side length (x+5) units
To find: area of square
<em><u>The area of square is given as:</u></em>
![\text {Area of square }=\mathrm{a}^{2}](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20square%20%7D%3D%5Cmathrm%7Ba%7D%5E%7B2%7D)
Where "a" is the length of side
From question, length of each side "a" = x + 5 units
Substituting the value in above formula,
![\text {Area of square }=(x+5)^{2}](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20square%20%7D%3D%28x%2B5%29%5E%7B2%7D)
![{\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}](https://tex.z-dn.net/?f=%7B%5Ctext%20%7BExpanding%20%7D%28x%2B5%29%5E%7B2%7D%20%5Ctext%20%7B%20using%20the%20algebraic%20identity%3A%20%7D%7D%20%5C%5C%5C%5C%20%7B%28a%2Bb%29%5E%7B2%7D%3Da%5E%7B2%7D%2B2%20a%20b%2Bb%5E%7B2%7D%7D%5Cend%7Barray%7D)
![\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7BArea%20of%20square%20%7D%3Dx%5E%7B2%7D%2B2%28x%29%285%29%2B5%5E%7B2%7D%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7BArea%20of%20square%20%7D%3Dx%5E%7B2%7D%2B10%20x%2B25%7D%5Cend%7Barray%7D)
Thus the area of square is
square units
Answer:
By angle sum property,
56 + 92 = 148
180 - 148 = 32
linear pair
so , 180 - 32
= 148
Hope it helps
Please mark me as the brainliest
Thank you