a) The point (2, -7/5) is not a point on the graph?
b) The value of f(x) when x is 1 is -1/3 and the point on the graph is (1, -1/3)
c) The value of x for f(x) = 2 is 22 and the point on the graph is (22, 2)
d) The domain of x is all real values of x ≠ 10
e) The x intercept is -2
f) The y intercept is -1/5
<h3>What is a Function?</h3>
Function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output and not one input for two outputs.
Analysis:
a) To test if the point (2, -7/5) is a point on the graph, we put in x = 2 into the function,
f(2) = 2+2/2-10 = 4/-8 = -1/2 ≠ -7/5. Therefore (2, -7/5) is not a point on the graph.
b) if x = 1, f(1) = 1 +2 / 1-10 = 3/-9 = - 1/3
The point on the graph is (1, -1/3)
c) if f(x) = 2, then 2 = x+2/x-10
2(x-10) = x+2
2x -20 = x+2
2x-x = 2+20
x = 22, the point on the graph is (22, 2)
d) The domain of the function is such that the denominator would not be zero.
so if x - 10 ≠ 0
Then the values of x ≠ 10 are the domain of the function.
e) The x intercept of the graph is the point at which f(x) = 0
0 = x+2/x-10
x+2 = 0
x = -2. The x-intercept is -2.
f) the y-intercept is such that x = 0
0+2/0-10 = 2/-10 = -1/5
Learn more about Function: brainly.com/question/25638609
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