I cant answer this on a computer sorry I would if I could though.
Answer:
you are on the right track
Step-by-step explanation:
the second ones right so you are right :)
For this case we have:
a = 30 cm
c = 16 cm
We look for the length of the diagonal:
d = x + y
Where,
For x:
a ^ 2 = x ^ 2 + x ^ 2
x = a / root (2) = 30 / root (2) = 21.2132 cm
For y:
c ^ 2 = y ^ 2 + y ^ 2
y = c / root (2) = 16 / root (2) = 11.3137 cm
The diagonal is:
d = x + y
d = 21.2132 + 11.3137
d = 32.5269 cm
Then, the height is:
h = h1 + h2
For h1:
h1 = root (x ^ 2 - (a / 2) ^ 2) = root ((21.2132) ^ 2 - (30/2) ^ 2)
h1 = 15 cm
For h2:
h2 = root (y ^ 2 - (c / 2) ^ 2) = root ((11.3137) ^ 2 - (16/2) ^ 2)
h2 = 8 cm
Finally:
h = h1 + h2
h = 15 + 8
h = 23 cm
Then, the area is:
A = (1/2) * (a + c) * (h)
A = (1/2) * (30 + 16) * (23)
A = 529 cm ^ 2
Answer:
the area of an isosceles trapezoid is:
A = 529 cm ^ 2
Answer:
166degrees
Step-by-step explanation:
Using the theorem which states that the angle at the vertex is twice the angle at the intercepted arc
Angle at the vertex <MNO = 83degrees
Angle at the arc = m<MLO
According to the theorem
83 = 1/2(m<MLO)
m<MLO = 83 * 2
m<MLO = 166degrees
Hence the measure of angle MLO is 166degrees
Answer:
20/2-50
Step-by-step explanation:
t = 20/2-50
