Answer:
5
Step-by-step explanation:
this can be solved using simultaneous equation
2a + 3b = 19 equation 1
1a + 4b = 17 equation 2
Multiply equation 2 by 2
2a + 8b = 34 equation 3
Subtract equation 1 from 3
5b = 15
b = 3
Substitute for b in equation 1
2a + 3(3) = 19
2a = 9 = 19
2a = 10
a = 5
Answer:
The selling price is $46 approx.
Step-by-step explanation:
The cost price is = $35.87
Markup is 22% of selling price.
Let the selling price be = 100%
So, 100%-22%=78% = 0.78
So, solution is =
≈ $46.
Hence, the selling price is $46 approx.
Answer:
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Answer:
(a) true
(b) true
(c) false; {y = x, t < 1; y = 2x, t ≥ 1}
(d) false; y = 200x for .005 < |x| < 1
Step-by-step explanation:
(a) "s(t) is periodic with period T" means s(t) = s(t+nT) for any integer n. Since values of n may be of the form n = 2m for any integer m, then this also means ...
s(t) = s(t +2mt) = s(t +m(2T)) . . . for any integer m
This equation matches the form of a function periodic with period 2T.
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(b) A system being linear means the output for the sum of two inputs is the sum of the outputs from the separate inputs:
s(a) +s(b) = s(a+b) . . . . definition of linear function
Then if a=b, you have
2s(a) = s(2a)
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(c) The output from a time-shifted input will only be the time-shifted output of the unshifted input if the system is time-invariant. The problem conditions here don't require that. A system can be "linear continuous time" and still be time-varying.
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(d) A restriction on an input magnitude does not mean the same restriction applies to the output magnitude. The system may have gain, for example.