More days recorded temperatures between 82 and 84 then other temperatures.
The least number of days recorded temperatures between 88 and 90.
The histogram is skewed to the right also known as positive skewed distribution.
The mean and median will most likely be in the range of 82-84 temperatures. But the mean will be greater than the median.

4 0

2 years ago

After 3.5 hours pasha had traveled to 17 miles if she travels at a constant speed how far will she have traveled after four hour

laiz [17]

Since we want to know how far she goes every hour to multiply that by 4 to get how far she goes in 4 hours, we do 17/3.5 to get per hour miles = around 4.86. Multiply that by 4 to get around 19.43 miles

4 0

3 years ago

1. What is the median of the data set?

Tamiku [17]

Answer: 1. 7

2. 100

3. 193.8

4. 0.8

5. 90.6

Step-by-step explanation:

1. Given the data 9,3,10,12,4,5,12,2

For finding the median we arrange it in ascending order

2,3,4,5,9, 10,12,12

Since the no of observations are even

∴ median = $\frac{n/2 th term + (n/2 + 1)th term}{2}$

= $\frac{5+9}{2}$

= $\frac{14}{2}$

i.e. Median =7

2. Given the data

23, 95,100,23,100,100

Since the no 100 is repeated thrice i.e. the maximum no of times

∴ Mode=100

Given the data

108, 305,252,113, 191

Mean= $\frac{108+305+252+113+191}{5}$

= $\frac{969}{5}$

=193.8

4. Money spent in the first week

= $11.52, $6.48, $5.99, $14.00, and $9.50

Total for the first week

=11.52+6.48+5.99+14.00+9.50

=$47.49

Now she spent $4 more in the second week

i.e.$47.49+4

=51.49$

Increase in mean = $\frac{4}{5}$

=0.8

Given

2 students scored 100 each

9 students scored 95 each

10 students scored 90 each

3 students scored 80 each

1 student scored 70

Total score of students = $2\times100+ 9\times 95+10\times90+3\times80+70\times1$

=2265

The average score

= $\frac{2265}{25}$

=90.6

8 0

2 years ago