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Murrr4er [49]
3 years ago
10

Variables make it easier to do what?

Computers and Technology
1 answer:
defon3 years ago
8 0
<span>D. Make changes to your code
Variables allow the ability to easily substitute numbers for other numbers.
</span>
You might be interested in
the volume of two similar solids are 1080cm and 1715cm .if the curved surface area of the smaller cone is 840cm .fond the curved
gavmur [86]

Answer:

A_{big} = 1143.33cm^2

Explanation:

The given parameters are:

V_{small} = 1080

V_{big} = 1715

C_{small} = 840

Required

Determine the curved surface area of the big cone

The volume of a cone is:

V = \frac{1}{3}\pi r^2h

For the big cone:

V_{big} = \frac{1}{3}\pi R^2H

Where

R = radius of the big cone and H = height of the big cone

For the small cone:

V_{small} = \frac{1}{3}\pi r^2h

Where

r = radius of the small cone and H = height of the small cone

Because both cones are similar, then:

\frac{H}{h} = \frac{R}{r}

and

\frac{V_{big}}{V_{small}} = \frac{\frac{1}{3}\pi R^2H}{\frac{1}{3}\pi r^2h}

\frac{V_{big}}{V_{small}} = \frac{R^2H}{r^2h}

Substitute values for Vbig and  Vsmall

\frac{1715}{1080} = \frac{R^2H}{r^2h}

Recall that:\frac{H}{h} = \frac{R}{r}

So, we have:

\frac{1715}{1080} = \frac{R^2*R}{r^2*r}

\frac{1715}{1080} = \frac{R^3}{r^3}

Take cube roots of both sides

\sqrt[3]{\frac{1715}{1080}} = \frac{R}{r}

Factorize

\sqrt[3]{\frac{343*5}{216*5}} = \frac{R}{r}

\sqrt[3]{\frac{343}{216}} = \frac{R}{r}

\frac{7}{6} = \frac{R}{r}

The curved surface area is calculated as:

Area = \pi rl

Where

l = slant\ height

For the big cone:

A_{big} = \pi RL

For the small cone

A_{small} = \pi rl

Because both cones are similar, then:

\frac{L}{l} = \frac{R}{r}

and

\frac{A_{big}}{A_{small}} = \frac{\pi RL}{\pi rl}

\frac{A_{big}}{A_{small}} = \frac{RL}{rl}

This gives:

\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{L}{l}

Recall that:

\frac{L}{l} = \frac{R}{r}

So, we have:

\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{R}{r}

\frac{A_{big}}{A_{small}} = (\frac{R}{r})^2

Make A_{big} the subject

A_{big} = (\frac{R}{r})^2 * A_{small}

Substitute values for \frac{R}{r} and A_{small}

A_{big} = (\frac{7}{6})^2 * 840

A_{big} = \frac{49}{36} * 840

A_{big} = \frac{49* 840}{36}

A_{big} = 1143.33cm^2

<em>Hence, the curved surface area of the big cone is 1143.33cm^2</em>

4 0
3 years ago
Determina la cilindrada total Vt en un motor de 4 cilindres de 83,6 mm de diàmetre per 91 mm de cursa.
insens350 [35]

Answer:

La cilindrada total del motor es de 1997,025 centímetros cúbicos.

Explanation:

Para determinar la cilindrada total Vt en un motor de 4 cilindros de 83,6 mm de diámetro por 91 mm de carrera se debe realizar el siguiente cálculo, sabiendo que para calcular la cilindrada de un motor se debe utilizar la fórmula ((Pi x Diámetro^2)/4) x Carrera x Número de cilindros = X:

((3.14 x 83.6^2)/4) x 91 x 4 = X

((3.14 x 6,988.96)/4) x 364 = X

(21,945.3344 / 4) x 364 = X

5,486.3336 x 364 = X

1,997,025.4304 = X

1 milímetro cúbico = 0.001 centímetro cúbico

1,997,025.4304 milímetros cúbicos = 1997.0254304000005 centímetros cúbicos

Por lo tanto, la cilindrada total del motor es de 1997,025 centímetros cúbicos.

3 0
3 years ago
A musician has recorded some initial ideas for new songs which she wishes to share with her bandmates. As these are initial idea
Ugo [173]

Answer:

1.save the audio using a low sampling rate

2.save the audio using a low bit depth

Explanation:

1. if the quality of the audio is low then the size of the audio will also be low and which will make the size of the data to be less and also easier to download

3 0
3 years ago
Consider a company that needs to sort an array of structures of type Customer by balance, with the largest balance first. Here i
8090 [49]

Answer:

#include <iostream>

#include <string>

#include <cstring>

#include <cstdlib>

using namespace std;

struct Person

{

string name;

int age;

};

int main()

{

struct Person data[10];

struct Person *pData[10],*temp;

string names[] = {"a","b","c","g","z","l","p","q","r","w"};

int num[] = {4,6,34,8,13,90,33,22,18,23};

for(int i=0;i<9;i++)

{

data[i].name = names[i];

data[i].age = num[i];

pData[i] = &data[i];

}

for(int i=0;i<9;i++)

{

for(int j=i+1;j<9;j++)

{

if(pData[i]->name.compare(pData[j]->name)>0)

{

temp = pData[i];

pData[i] = pData[j];

pData[j] = temp;

}

}

}

for(int i=0;i<9;i++)

{

cout<<pData[i]->name<<" "<<pData[i]->age<<endl;

}

}

Explanation:

The line #include <iostream> initializes the program.

This program created an array of only 10 structures, Customer data. Also defined an auxiliary array Customer *pData.

The program uses these parameters to sorts the array of pointers so that when you go through pData in increasing order of index k, the entries pData[k] point to Customer objects in decreasing order by balance, meaning that pdata[0] now points to the customer with the highest balance, and pData[9] points to the customer with the smallest balance.

4 0
3 years ago
Identify the three fuzzy logic systems in the given text.
Furkat [3]

Answer:

she is the both city CAA been Van from is next

4 0
3 years ago
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