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frozen [14]
2 years ago
12

Universal Containers is implementing a community of High-Volume Community users. Community users should be able to see records a

ssociated to their Account or Contact record. The Architect is planning to use a Sharing Set to provide access to the records. When setting up the Sharing Set, certain objects are not available in the list of Available objects.Which two reasons explain why an object is excluded from the list of Available objects in a Sharing Set?Choose 2 answers
A. The custom object does not have a lookup to Accounts or ContactsB. The object’s Organization-Wide sharing setting is set to PrivateC. The object’s Organization-Wide setting is set to Public Read/WriteD. The object is a custom object, and therefore not available for a sharing set
Computers and Technology
1 answer:
Aneli [31]2 years ago
7 0

Answer:

The answers are A and C

Explanation:

The reason the objects were excluded from the list of available objects are as follows:

A.) The custom object does not have a lookup to Accounts or Contacts

C.) The object's Organization-Wide sharing setting is set to Public Read/Write.

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write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average​
bekas [8.4K]

Answer:

#include <stdio.h>  

int MaxMark(int* arr, int size) {

   int maxMark = 0;

   if (size > 0) {

       maxMark = arr[0];

   }

   for (int i = 0; i < size; i++) {

       if (arr[i] > maxMark) {

           maxMark = arr[i];

       }

   }

   return maxMark;

}

int SumMarks(int* arr, int size) {

   int sum = 0;

   for (int i = 0; i < size; i++) {

       sum += arr[i];

   }

   return sum;

}

float AvgMark(int* arr, int size) {

   int sum = SumMarks(arr, size);

   return (float)sum / size;

}

int main()

{

   int student0[] = { 7, 5, 6, 9 };

   int student1[] = { 3, 7, 7 };

   int student2[] = { 2, 8, 6, 1, 6 };

   int* marks[] = { student0, student1, student2 };

   int nrMarks[] = { 4, 3, 5 };

   int nrStudents = sizeof(marks) / sizeof(marks[0]);

   for (int student = 0; student < nrStudents; student++) {              

       printf("Student %d: max=%d, sum=%d, avg=%.1f\n",  

           student,

           MaxMark(marks[student], nrMarks[student]),

           SumMarks(marks[student], nrMarks[student]),

           AvgMark(marks[student], nrMarks[student]));

   }

   return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

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3 years ago
Given the following code fragment and the input value of 4.0, what output is generated?
kicyunya [14]

Answer:

c) 4.4

Explanation:

You can evaluate step by step the code. You know tha your input is 4.0

Step 1 Variables definitions:

double tax;

double total;

Step 2 Ask the user for the input:

System.out.print("Enter the cost of the item");

Step 3 read de input:

total = scan.nextDouble();

Step 4 evaluate the condition (  is the input greater or equal  than 3.0 ? [True])

if ( total >= 3.0)

Step 5 get done the operations inside the condition and print it:

tax = 0.10;

System.out.println(total + (total * tax));

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I have a question about my HP Laptop
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